hysteresis curve
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A ferromagnetic material has a remanence of 1.5 T and a coercivity of 50,000 A/m.
Saturation is achieved at a magnetic field intensity of 200,000 A/m, at which the flux
density is 2.5 T. Using these data, sketch the entire hysteresis curve in the range
H= −200,000 to +200,000 A/m
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- A ferromagnetic core in the shape of a doughnut has a cross-sectional area of 0.11 m2 and an average length of 1.4 m. The permeabil ity of the core is 1.206 × 10-3 Wb/A-t. m. Determine the reluctance of the magnetic circuitA ring of ferromagnetic material has a rectangular section. The inner diameter is 15 cm.The outer diameter is 24 cm. And the thickness is 5 cm. There is a coil of 500 turns wound onthe ring. When the coil has a current of 10 A, the flux in the core is 0.0007 Wb. Theaverage length of the ring is Ln=0.66m Determine:a) The magnetomotive force.b) The intensity of the magnetic field and the flux density.c) Reluctance, permeability and relative permeability.An air core toroidal coil has 120 turns, the length is 12 cm and 12 sq. cm in area What is the current required to set up a flux of 1.2x10° weber. What is the current?
- Consider a ferromagnetic ring (nucleus) that has a mean circumference of 40 cm, 300coiled copper turns and a sectional area of 5 cm2. A current of 2 is appliedA to winding, producing a flux of 1.5 mWb.Determine the permeability of the core material.Determine the relative permeability of the core material.If the ferromagnetic ring has an air gap of 2 mm. Find the required MMFso that the flux density in the gap is 0.5 T.A coil that con sists of 450 windings is wound aroundabakelite ring. The mean diameter of the ring is 100 mm and the diameter of the bakelite core is 20 mm. The currentthrough the coil is 3 A. Determine: 1.1 a) the field stren gth b) the flux den sity c) the total flux A ringhas two halves. The onehalf is made from Cast iron, while the other is made from Cast steel. The two halves are held 1 mm apart with the aid of a paper disc. The cross-section al area and mean circumference of the ringis 345 mm? and0.6 m respectively. Therelative permeability of cast iron is 2400, while that of cast steel is 600. The ring has a coil with 200 win dings. The currentflow through the coil causes a flux den sity of 0.48T. 1.2 Calculate the: a) mmi b) currentflow Ignore the effects of fringing andleakage.a rectangular ferromagnetic core 40 x 60 mm has a flux φ = 1.44 mwb. an air gap in the core is of length la = 2.5 mm. find the ni drop across the air gap.
- A ferromagnetic core with a relative permeability of 1500 is shown in the given figure. The dimensions are as shown in the diagram, and the depth of the core is 5 cm. The air gaps on the left and right sides of the core are 0.050 and 0.070 cm, respectively. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 300 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A: (a) What are the flux values for the left, center and the right legs of the core? (b) What is the flux density in each air gap? 7 cm -30 cm- 7 em 30 ст 7 cm 30 cm -0.07 cm 300 turns 0.05 cm- 7 сm Core depth = 5 cmA ferromagnetic core with a relative permeability of 1500 is shown in the given figure. The dimensions are as shown in the diagram, and the depth of the core is 5 cm. The air gaps on the left and right sides of the core are 0.050 and 0.070 cm, respectively. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 300 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A: (a) What are the flux values for the left, center and the right legs of the core? (b) What is the flux density in each air gap? 30 cm- 30 cm 7 cm 30 cm 0.07 cm 300 turns 0.05 cm cm Core depth - 5 cmA ferromagnetic core with a relative permeability of 1500 is shown in the given figure. The dimensions are as shown in the diagram, and the depth of the core is 5 cm. The air gaps on the left and right sides of the core are 0.050 and 0.070 cm, respectively. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 300 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A: (a) What are the flux values for the left, center and the right legs of the core? (b) What is the flux density in each air gap? 7 cm 30 cm 30cm- 7 cm 30 cm 0.07 cm 300 turns 0.05 cm 7 cm Activate Windows Go to Settings to activate Windows. Core depth - 5 cm
- A magnetic ring has reluctance of 1.675 × 10⁰ AT weber. The flux to be produced by the coil is 800 x 10 webers, then the AT required for the m.m.f. will beA flux of 0.0016 Wb flows in a silicon sheet steel coil/core. The arrangement appears as shown below with the following dimensions: Ac = 0.0025 m? Core/gap area: Flux path length: le = 0.350 m lg = 0.0015 m N = 500 Air gap length: Number of turns: %3D A. What is the current, I, through the winding? B. What is the energy stored in the inductance? C. Assume that the current is given by i =9.75 sin (3147) A. What is the RMS voltage that would appear across the winding? D. Assume that the gap is removed from the arrangement with the flux path remaining at 0.350 m. For a flux of 0.0016 Wb, what is the inductance of the arrangement? E. What is the energy stored in the inductance with the gap removed?The magnetic structure of Figure Q7 1 has a rerromagnetic core that can be treated as infinitely permeable Air-gap fringing Is negligible Let N= 10 turns, A=02 m and gap length is 0 = 5 x 10 m. The coil is excited by a sinusoidal voltage source that establishes a flux given by p(t) = 0.25stn20t Wb. The resistance of the coil can be neglected Determine the supply voltage, ), the current, (t) and the inductance of the coil, L. %3D Area, A ŁAir Vst) Figure Q7.1. Solutions insert your solutions in the spaces provided below. Give your numerical values to the nearest whole number unless where stated otherwise. Veft) = Volts t) = A. L= H (give your answer correct to 3 decimal places).