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HW1- Derive the integral forms of Maxwell's equations and the continuity equation from the differential form.

HW1- Derive the integral forms of Maxwell's equations and the continuity equation from the differential form.

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apv Q1-Derive the differential form of the continuity equation V.J+ = 0 using Maxwell's Equations. at Solution: From Ampere's law we have aD V x H = J+ at Taking the divergence of both sides V. (V x H) = V.J+V. 7 (210) = √ V.J + V. at Using the vector identity of V. (V x A) = 0 And Gauss law for electric field V.D = Pu We get that the left-hand side equals Zero and we arrange the right-hand side to apv 0 = V.J+ a at V.D = V.J+ at HW1- Derive the integral forms of Maxwell's equations and the continuity equation from the differential form. V.D
Transcribed Image Text:apv Q1-Derive the differential form of the continuity equation V.J+ = 0 using Maxwell's Equations. at Solution: From Ampere's law we have aD V x H = J+ at Taking the divergence of both sides V. (V x H) = V.J+V. 7 (210) = √ V.J + V. at Using the vector identity of V. (V x A) = 0 And Gauss law for electric field V.D = Pu We get that the left-hand side equals Zero and we arrange the right-hand side to apv 0 = V.J+ a at V.D = V.J+ at HW1- Derive the integral forms of Maxwell's equations and the continuity equation from the differential form. V.D
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