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Transcribed Image Text:apv
Q1-Derive the differential form of the continuity equation V.J+ = 0 using Maxwell's Equations.
at
Solution: From Ampere's law we have
aD
V x H = J+
at
Taking the divergence of both sides
V. (V x H) = V.J+V.
7 (210) = √
V.J + V.
at
Using the vector identity of
V. (V x A) = 0
And Gauss law for electric field
V.D = Pu
We get that the left-hand side equals Zero and we arrange the right-hand side to
apv
0 = V.J+
a
at
V.D = V.J+
at
HW1- Derive the integral forms of Maxwell's equations and the continuity equation from the differential
form.
V.D
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