College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Related questions
Concept explainers
Question
How to solve part 2 of this question? I have an answer of 1.97E22 for part A but I am having trouble with part B.
A. The Earth has a mass of 5.97 * 1024 kg and the Moon has a mass of 7.35 * 1022 kg. If they are separated by a distance of 3.85 * 105 km, what is the force (in N) between the Earth and the Moon? (Enter your answer in scientific notation: 1.23E12 means 1.23 * 1012)
B. Repeat the previous problem using
Expert Solution
arrow_forward
Step 1
Given data:
Mass of moon,
Distance between earth and Moon,
Time taken to complete one circle by moon around Earth, T = 27.32 days
Trending nowThis is a popular solution!
Step by stepSolved in 3 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Migrating land mammals are often called runners because of the large distances that they can cover in one day. The velocity (speed) of a migrating land mammal or runner in relation to its mass can be modeled by the equation V(m) = 9.31m0.12, where m is the mass of the animal in kilograms and V is the velocity in kilometers per day. Round your answers to the tenths place, if necessary. Part A: Complete the table by determining the velocity of several different runners. Animal Mass (kg) Velocity (km/day) Grey Wolf 40 14.494 OB Zebra American Buffalo African Elephant 270 900 5000 Answer: It will travel 1 18.227 Part B: How does the mass of the elephant compare to the mass of the zebra? How do their velocities compare? 21.062 X Answer: The mass of the elephant is 18.51 elephant is 1.419 x times that of the zebra. Answer: Answer: The mass of the buffalo is 22.5 1.5 ✓o times that of the wolf. OB 25.872✓ O Part C: How does the mass of the buffalo compare to the mass of the wolf? How do their…arrow_forwarda) Observations and trigonometry can be used to determine that Earth's moon has an orbital period of 27.32 days and a mean orbital radius of 384,400 km. Using this information, calculate the mass of the Earth. 2 M = 47² ² 2 C M= 4+1 (30214100000) 667 earrow_forwardIn the year 25 000 the Earth is 1.42x101 m away from the sun and in a circular orbit, but a year remains 365 days long. Part A Calculate the mass of the sun in the year 25 000. ΑΣΦ ? msun = kgarrow_forward
- Exoplanet Taphao Keow is a Jupiter-sized planet orbiting another star. It has a mass of approximately 1×10+27[kg]. Its actual radius is not currently known, but we do know that the radius of Jupiter is 7×107[m]. Question: If Taphao Keow had a radius that was the same radius as Jupiter, what would it's local surface gravitational acceleration be? O 266 [m/s2] 124 [m/s²] 70 [m/s²] O 24 [m/s²] O 14 [m/s²] It would have a gravitational acceleration far larger than any of the other answers (many orders of magnitude larger) It would have a gravitational acceleration far smaller than any of the other answers (many orders of magnitude larger)arrow_forwardQUESTION 4 It is year 2321, and humans colonized Mars. You are in an elevator on a Martian skyscaper and you are standing on a bathroom scale of mass 1.1 kg. Your mass is 74.3 kg. The mass of the elevator car is given as 1,175 kg. While the elevator is moving you notice that the bathroom scale shows your weight as 325.2 Newtons. What should be accelaration of the elevator at the moment you read your weight? Enter your answer by taking the upward direction as the positive direction in units of m/s. (accelaration due to gravity magnitude on Mars surface is 3.75 m/s2)arrow_forwardCalculate the mass (in SI units) of a 140 lblb human being. Express your answer with the appropriate units.arrow_forward
- 2.arrow_forwardNewton's law of universal gravitation is represented by Mm F = G- where F is the gravitational force, M and m are masses, and r is a length. Force has the SI units kg · m/s2. What are the SI units of the proportionality constant G? m3 kg - s2 m kg ·s3 m2 kg · s2 m2 kg · 3arrow_forwardI-C.arrow_forward
- The class I'm taking is physics for scientists and engineers! I am completely stuck. Need help. I have attached the problem. Please view both attachments before answering. Please write step-by-step solution so I can fully understand.arrow_forwardWe will use differential equations to model the orbits and locations of Earth, Mars, and the spacecraft using Newton’s two laws mentioned above. Newton’s second law of motion in vector form is: F^→=ma^→ (1) where F^→ is the force vector in N (Newtons), and a^→ is the acceleration vector in m/s^2,and m is the mass in kg. Newton’s law of gravitation in vector form is: F^→=GMm/lr^→l*r^→/lr^→l where G=6.67x10^-11 m^3/s^2*kg is the universal gravitational constant, M is the mass of the larger object (the Sun), and is 2x10^30 kg, and m is the mass the smaller one (the planets or the spacecraft). The vector r^→ is the vector connecting the Sun to the orbiting objects. Step one ) The motion force in Equation(1), and the gravitational force in Equation(2) are equal. Equate the right hand sides of equations (1) and (2), and cancel the common factor on the left and right sides. Answer: f^→=ma^→ f=Gmm/lr^→l^2 a^→=Gmm/lr^→l^2 x r^→/lr^→l r^→=r^→/lr^→l * Gmm Could you please…arrow_forwardAsteroid Toutatis passed near Earth in 2006 at four times the distance to our Moon. This was the closest approach we will have until 2060. If it has mass of 4.1 x 1013 kg, what force did it exert on Earth at its closest approach? Use 384400 km for the distance between the earth and the moon, and 5.972 1024 kg for the mass of the earth. Help on how to format answers: units F =arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
University Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSON
Introduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press 
Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Lecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON