Question
how to solve for the density of air? can anyone explain why the answer is =0.00191 slug/ft^3?

Transcribed Image Text:Given
P= 10psi
T= -20°F
We know that,
Density of air at a state is given by,
%3D
RT
P =(10psi) (144 fn/4f¢) =
I=(-20°F+ 460o)°R = 440°R
& R 1716 ft.llof Islug.°R
2
where
140 ebf/ft?
%3D
%3D
There fore,
2
1440 lbf/ft
(1716 ft Bbf/slug.R) (440°R)
3=0.00191 slylft'
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