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How much mass (in grams) of aluminum initially at 150 °C must be added to 300 g of water initially at 20.0 °C to make the final equilibrium temperature 80 °C? specific heat of aluminum = 0.215 cal/g.K, and specific heat of water = 1 cal/g.K

How much mass (in grams) of aluminum initially at 150 °C must be added to 300 g of water initially at 20.0 °C to make the final equilibrium temperature 80 °C? specific heat of aluminum = 0.215 cal/g.K, and specific heat of water = 1 cal/g.K

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How much mass (in grams) of aluminum initially at 150 °C must be added to 300 g of water initially at 20.0 °C to make the final equilibrium temperature 80 °C? specific heat of aluminum = 0.215 cal/g.K, and specific heat of water = 1 cal/g.K
Transcribed Image Text:How much mass (in grams) of aluminum initially at 150 °C must be added to 300 g of water initially at 20.0 °C to make the final equilibrium temperature 80 °C? specific heat of aluminum = 0.215 cal/g.K, and specific heat of water = 1 cal/g.K
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