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How much heat is required to change 472 g of ice at -11°C to steam at 106°C? cice = 2090 J/kg C c water = 4184 J/kg C c steam = 2020 J/kg C Lf = 335,000 J/kg Lv = 2,256,000 J/kg Find the heat necessary to turn 8 kg of ice at -8 into water at 11. c Ice = 2090 J/(kg oC) c Water = 4187 J/(kg oC) c Steam = 1996 J/(kg oC) Lf = 335,000 J/kg Lv = 2,260,000 J/kg In order to change some amount of ice at 0 deg C into steam at 110 deg C, there are four steps: • melt the ice into water • heat the water that used to be ice • boil the water into steam • heat the steam Which step requires the most heat? c Ice = 2090 J/(kg oC) c Water = 4187 J/(kg oC) c Steam = 1996 J/(kg oC) Lf = 335,000 J/kg Lv = 2,260,000 J/kg A) melt the ice into water

How much heat is required to change 472 g of ice at -11°C to steam at 106°C? cice = 2090 J/kg C c water = 4184 J/kg C c steam = 2020 J/kg C Lf = 335,000 J/kg Lv = 2,256,000 J/kg Find the heat necessary to turn 8 kg of ice at -8 into water at 11. c Ice = 2090 J/(kg oC) c Water = 4187 J/(kg oC) c Steam = 1996 J/(kg oC) Lf = 335,000 J/kg Lv = 2,260,000 J/kg In order to change some amount of ice at 0 deg C into steam at 110 deg C, there are four steps: • melt the ice into water • heat the water that used to be ice • boil the water into steam • heat the steam Which step requires the most heat? c Ice = 2090 J/(kg oC) c Water = 4187 J/(kg oC) c Steam = 1996 J/(kg oC) Lf = 335,000 J/kg Lv = 2,260,000 J/kg A) melt the ice into water

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Please need help with three part question on ice and temp(heat) thank you.
How much heat is required to change 472 g of ice at -11°C to steam at 106°C? cice = 2090 J/kg C c water = 4184 J/kg C c steam = 2020 J/kg C Lf = 335,000 J/kg Lv = 2,256,000 J/kg Find the heat necessary to turn 8 kg of ice at -8 into water at 11. c Ice = 2090 J/(kg oC) c Water = 4187 J/(kg oC) c Steam = 1996 J/(kg oC) Lf= 335,000 J/kg Lv = 2,260,000 J/kg In order to change some amount of ice four steps: • melt the ice into water heat the water that used to be ice • boil the water into steam heat the steam Which step requires the most heat? c Ice = 2090 J/(kg oC) c Water = 4187 J/(kg oC) c Steam = 1996 J/(kg oC) Lf = 335,000 J/kg Lv = 2,260,000 J/kg A) melt the ice into water B) heat the water that used to be ice C) boil the water into steam D) heat the steam deg C steam at 110 deg the e are
Transcribed Image Text:How much heat is required to change 472 g of ice at -11°C to steam at 106°C? cice = 2090 J/kg C c water = 4184 J/kg C c steam = 2020 J/kg C Lf = 335,000 J/kg Lv = 2,256,000 J/kg Find the heat necessary to turn 8 kg of ice at -8 into water at 11. c Ice = 2090 J/(kg oC) c Water = 4187 J/(kg oC) c Steam = 1996 J/(kg oC) Lf= 335,000 J/kg Lv = 2,260,000 J/kg In order to change some amount of ice four steps: • melt the ice into water heat the water that used to be ice • boil the water into steam heat the steam Which step requires the most heat? c Ice = 2090 J/(kg oC) c Water = 4187 J/(kg oC) c Steam = 1996 J/(kg oC) Lf = 335,000 J/kg Lv = 2,260,000 J/kg A) melt the ice into water B) heat the water that used to be ice C) boil the water into steam D) heat the steam deg C steam at 110 deg the e are
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