Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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**Question:**  
How much heat is absorbed in the process of making 0.793 mol of CF₄ from the following reaction?  

\( \text{C (s) + 2 F}_2 \text{(g)} \rightarrow \text{CF}_4 \text{(g)} \quad \Delta H^\circ = 141.3 \, \text{kJ/mol} \)

**Explanation:**  
This equation describes the formation of carbon tetrafluoride (CF₄) from carbon (C) and fluorine gas (F₂). The enthalpy change (ΔH°) for this reaction is 141.3 kJ per mole of CF₄ formed. To find out how much heat is absorbed for 0.793 moles, you multiply the enthalpy change by the number of moles:

\[
\text{Heat absorbed} = 0.793 \, \text{mol} \times 141.3 \, \text{kJ/mol} = 112.0599 \, \text{kJ}
\]

Thus, 112.06 kJ of heat is absorbed in the process.
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Transcribed Image Text:**Question:** How much heat is absorbed in the process of making 0.793 mol of CF₄ from the following reaction? \( \text{C (s) + 2 F}_2 \text{(g)} \rightarrow \text{CF}_4 \text{(g)} \quad \Delta H^\circ = 141.3 \, \text{kJ/mol} \) **Explanation:** This equation describes the formation of carbon tetrafluoride (CF₄) from carbon (C) and fluorine gas (F₂). The enthalpy change (ΔH°) for this reaction is 141.3 kJ per mole of CF₄ formed. To find out how much heat is absorbed for 0.793 moles, you multiply the enthalpy change by the number of moles: \[ \text{Heat absorbed} = 0.793 \, \text{mol} \times 141.3 \, \text{kJ/mol} = 112.0599 \, \text{kJ} \] Thus, 112.06 kJ of heat is absorbed in the process.
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