How much heat (in kJ mol–1 to two decimal places) is required to vaporize 2.5 moles of benzene (C6H6; 78.11 g mol–1) at its normal boiling point using the given enthalpy of vaporization? ΔH=30.72 kJ mol-1

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.51QE: The enthalpy change when 1 mol methane (CH4) is burned is 890 kJ. It takes 44.0 kJ to vaporize 1 mol...
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How much heat (in kJ mol–1 to two decimal places) is required to vaporize 2.5 moles of benzene (C6H6; 78.11 g mol–1) at its normal boiling point using the given enthalpy of vaporization?

ΔH=30.72 kJ mol-1

 

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