How much energy is required to heat 8.6kg of ice from -20℃ to steam at 120C ? The specific heat capacity of ice is 2.097 J/kg C The latent heat of fusion of ice is: Lf = 3.33 × 105J/kg The specific heat capacity of water is 4186J/kg C The latent heat of vaporization of water is: Lv = 22.6 × 105J/kg The specific heat capacity of steam is 1996 J/kg°C DO NOT include units. DO NOT write in scientific notation. Do not include any "spaces" in your answer. 1. The heat energy needed to raise the temperature of ice to 0 degrees Celcius (in Joules) = 2. The heat energy needed to convert ice to water at 0 degrees Celcius (in Joules) = 3. The heat energy needed to raise the temperature of water from 0 degrees to 100 degrees Celcius (in Joules)=

An ice tray is removed from a freezer, where the ice was at a temperature of -11°C, and left on a countertop. If the mass of the ice is 0.29 kg, how much heat must be added in k to turn all the ice into room temperature water (that is, liquid water at 20°C)? The specific heat of water is 4.2 kgC kJ the heat of fusion of water is 335 kg kJ and the specific heat of ice is 2.1 kg°C* 133.69 This is a change of phase question. There are 3 cases we have to consider: 1. The heat required to increase the temperature of the ice, Q1 2. The heat required to turn the ice into a liquid (a phase change), Q2 3. The heat required to raise the temperature of the now liquid water, Q3 For Q1, you will use the equation Q = mcATusing the c=2.1 kJ/(kg*C). Keep in mind that the hp

How much heat energy in unit calorie is given up when 2 0.0 g of steam at 100.0 oC is condensed and cooled to 20.0 oC?

A 50 g ice cube at 00C is heated until 45 g has become water at 1000C and 5 g has become steam at 1000C. Determine the amount of heat that can be added to accomplish this? [ Cwater = 4186Jkg-1k-1, Lv = 2.26 * 10⁶ Jkg-1, Lf=3.33 * 105Jkg-1