How many moles of sodium are needed to react with 15.20 moles of manganese (IV) perchlorate? _Mn(CIO)4 +_Na→ _NaCIO + _Mn

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## Question (10 points):

**How many moles of sodium are needed to react with 15.20 moles of manganese (IV) perchlorate?**

__Mn(ClO₄)₄ + __Na → __NaClO + __Mn

---

To determine the number of moles of sodium (Na) needed to react with 15.20 moles of manganese (IV) perchlorate (Mn(ClO₄)₄), we first need to balance the chemical equation. After balancing the equation, we can use stoichiometry to calculate the required moles of sodium.

### Steps to Balance the Equation:

1. **Identify the Reactants and Products:**
   - Reactants: Manganese (IV) perchlorate (Mn(ClO₄)₄) and Sodium (Na)
   - Products: Sodium perchlorate (NaClO) and Manganese (Mn)

2. **Balance the Elements Other Than H and O:**
   - Manganese (Mn) appears once on both sides.
   - Sodium (Na) needs to be balanced.

3. **Balance Oxygen and Hydrogen (if any):**
   - There are 4 ClO₄ groups on the left side, which means 4 NaClO on the right side.

4. **Verify the Balance:**
   - Ensure the number of atoms of each element is equal on both sides.

By going through this methodical balancing process, we'll identify the stoichiometric coefficients for each compound.

*Note: Typically, detailed steps for balancing reactions are shown, but simplest approach may involve trial and error while confirming all elements are balanced.*

These balanced coefficients will let us determine the mole ratio between manganese (IV) perchlorate and sodium.

### Stoichiometry Calculation

After balancing, use the balanced equation to perform a stoichiometric calculation:
   - From the balanced equation, determine the mole ratio between Mn(ClO₄)₄ and Na.
   - Use this ratio to find out how many moles of sodium are needed for 15.20 moles of manganese (IV) perchlorate. 

This careful analysis will ensure an accurate understanding of the required sodium moles.
Transcribed Image Text:## Question (10 points): **How many moles of sodium are needed to react with 15.20 moles of manganese (IV) perchlorate?** __Mn(ClO₄)₄ + __Na → __NaClO + __Mn --- To determine the number of moles of sodium (Na) needed to react with 15.20 moles of manganese (IV) perchlorate (Mn(ClO₄)₄), we first need to balance the chemical equation. After balancing the equation, we can use stoichiometry to calculate the required moles of sodium. ### Steps to Balance the Equation: 1. **Identify the Reactants and Products:** - Reactants: Manganese (IV) perchlorate (Mn(ClO₄)₄) and Sodium (Na) - Products: Sodium perchlorate (NaClO) and Manganese (Mn) 2. **Balance the Elements Other Than H and O:** - Manganese (Mn) appears once on both sides. - Sodium (Na) needs to be balanced. 3. **Balance Oxygen and Hydrogen (if any):** - There are 4 ClO₄ groups on the left side, which means 4 NaClO on the right side. 4. **Verify the Balance:** - Ensure the number of atoms of each element is equal on both sides. By going through this methodical balancing process, we'll identify the stoichiometric coefficients for each compound. *Note: Typically, detailed steps for balancing reactions are shown, but simplest approach may involve trial and error while confirming all elements are balanced.* These balanced coefficients will let us determine the mole ratio between manganese (IV) perchlorate and sodium. ### Stoichiometry Calculation After balancing, use the balanced equation to perform a stoichiometric calculation: - From the balanced equation, determine the mole ratio between Mn(ClO₄)₄ and Na. - Use this ratio to find out how many moles of sodium are needed for 15.20 moles of manganese (IV) perchlorate. This careful analysis will ensure an accurate understanding of the required sodium moles.
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