How many moles of Mg*2 in 6.00 mL of a 6.0 N Mg3(PO4)2 solution ?First we have to convert moles into equivalentsMg3(PO4)23 Mg*22 PO43+1 mol =equivalents1 mol MP =mol Mg*2eqmol(6.00 x 10-3 L)(-%3Deq MP-) =eqmol Mg*2mol MP)(--) =mol Mg*2mol MPа. 250.b. 100.0С. 2d. 30.00е. 6f. 24g. 3h. 36i. 18.0j. 1k. 6.00 x 10-3I. 3.60 x 10-2m. 6.00 x 10-2n. 5О. 3.0 х 102p. 1.80 x 10-2q. 7.65 x 10-10r. 2.63S. 7.89t. 5.26и. 1012v. 109w. 106Х. 103у. 95.21z. 10

Given, Normality of Mg3(PO4)2 = 6.0 N Volume of Mg3(PO4)2 = 6.00 mL Find number of moles of Mg2+…

How many moles of Mg*2 in 6.00 mL of a 6.0N Mg3(PO4)2 Solution ? First we have to convert moles into equivalents Mg3(PO4)2 3 Mg*2 + 2 PO43 1 mol = equivalents 1 mol MP = mol Mg*2 eq mol (6.00 x 10-3 L)(- eq MP (- eq mol Mg*2 mol MP)(- -) = mol Mg*2 mol MP а. 250. b. 100.0 с. 2 d. 30.00 е. 6 f. 24 g. 3 h. 36 i. 18.0 j. 1 k. 6.00 x 10-3 I. 3.60 x 10-2 m. 6.00 x 10-2 n. 5 o. 3.0 x 10-2 p. 1.80 x 10-2 q. 7.65 x 10-10 r. 2.63 S. 7.89 t. 5.26 u. 1012 V. 109 w. 106 х. 103 у. 95.21 z. 10

How many moles of Mg2 in 6.00 mL of a 6.0N Mg3(PO4)2 Solution ? First we have to convert moles into equivalents Mg3(PO4)2 3 Mg2 + 2 PO43 1 mol = equivalents 1 mol MP = mol Mg2 eq mol (6.00 x 10-3 L)(- eq MP (- eq mol Mg2 mol MP)(- -) = mol Mg*2 mol MP а. 250. b. 100.0 с. 2 d. 30.00 е. 6 f. 24 g. 3 h. 36 i. 18.0 j. 1 k. 6.00 x 10-3 I. 3.60 x 10-2 m. 6.00 x 10-2 n. 5 o. 3.0 x 10-2 p. 1.80 x 10-2 q. 7.65 x 10-10 r. 2.63 S. 7.89 t. 5.26 u. 1012 V. 109 w. 106 х. 103 у. 95.21 z. 10

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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