Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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How many grams of the excess reactant remain after the limiting reactant is completely consumed?
Express your answer in grams to three significant figures.

The fizz produced when an Alka-Seltzer®® tablet is dissolved in water is due to the reaction between sodium bicarbonate (NaHCO3NaHCO3) and citric acid (H3C6H5O7H3C6H5O7): 3NaHCO3(aq)+H3C6H5O7(aq)→3CO2(g)+3H2O(l)+Na3C6H5O7(aq)3NaHCO3(aq)+H3C6H5O7(aq)→3CO2(g)+3H2O(l)+Na3C6H5O7(aq) In a certain experiment, 1.40 gg of sodium bicarbonate and 1.40 gg of citric acid are allowed to react.

How many grams of carbon dioxide form?
The fizz produced when an Alka-Seltzer" tablet is dissolved in water is due to the
reaction between sodium bicarbonate (NaHCO,) and citric acid (H3C,H;O-):
Express your answer in grams to three significant figures.
3NAHCO: (aq) + H;C,H;O; (aq) → 3CO2 (g) + 3H,O(1) + Na:C¢ H;O; (aq)
m = 0.733 g
In a certain experiment, 1.40 g of sodium bicarbonate and 1.40 g of citric acid are
allowed to react.
Submit
Previous Answers
v Correct
Since NaHCO3 is the limiting reactant, the amount of available NaHCO3 determines the amount of CO2
produced. Calculate the amount of CO2 produced using the conversion factor derived from the stoichiometric
ratio in the balanced chemical equation. Start with the number of moles of NaHCO3 calculated in Part A:
3 mol CO2
moles CO2 = 1.67 × 10 2 mol NaHCO x
= 1.67 x 10-2 mol CO2
3 mol NaHCO3
Convert the number of moles of CO2 to grams using the molar mass of CO2 as a conversion factor:
44.01 g CO2
grams CO2 =1.67 × 10–2
mol CO, x
= 0.733 g CO2
1 mol CO2
Part C
How many grams of the excess reactant remain after the limiting reactant is completely consumed?
Express your answer in grams to three significant figures.
?
Submit
Request Answer
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Transcribed Image Text:How many grams of carbon dioxide form? The fizz produced when an Alka-Seltzer" tablet is dissolved in water is due to the reaction between sodium bicarbonate (NaHCO,) and citric acid (H3C,H;O-): Express your answer in grams to three significant figures. 3NAHCO: (aq) + H;C,H;O; (aq) → 3CO2 (g) + 3H,O(1) + Na:C¢ H;O; (aq) m = 0.733 g In a certain experiment, 1.40 g of sodium bicarbonate and 1.40 g of citric acid are allowed to react. Submit Previous Answers v Correct Since NaHCO3 is the limiting reactant, the amount of available NaHCO3 determines the amount of CO2 produced. Calculate the amount of CO2 produced using the conversion factor derived from the stoichiometric ratio in the balanced chemical equation. Start with the number of moles of NaHCO3 calculated in Part A: 3 mol CO2 moles CO2 = 1.67 × 10 2 mol NaHCO x = 1.67 x 10-2 mol CO2 3 mol NaHCO3 Convert the number of moles of CO2 to grams using the molar mass of CO2 as a conversion factor: 44.01 g CO2 grams CO2 =1.67 × 10–2 mol CO, x = 0.733 g CO2 1 mol CO2 Part C How many grams of the excess reactant remain after the limiting reactant is completely consumed? Express your answer in grams to three significant figures. ? Submit Request Answer
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