How many grams of H2 can be formed from 87.2 grams of NH3 in the following reaction? 2 NH3(g) 3 H2 (g) + N2 (g)

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Question on Chemical Reaction:**

How many grams of \( \text{H}_2 \) can be formed from 87.2 grams of \( \text{NH}_3 \) in the following reaction?

\[ 2 \, \text{NH}_3(g) \rightarrow 3 \, \text{H}_2(g) + \text{N}_2(g) \]

**Explanation:**

This equation represents a chemical reaction where ammonia (\( \text{NH}_3 \)) decomposes to form hydrogen gas (\( \text{H}_2 \)) and nitrogen gas (\( \text{N}_2 \)). The coefficients indicate the molar ratios of the reactants and products:
- 2 moles of \( \text{NH}_3 \) produce 3 moles of \( \text{H}_2 \) and 1 mole of \( \text{N}_2 \).

To determine the amount of \( \text{H}_2 \) formed from a given mass of \( \text{NH}_3 \), follow these general steps:
1. Convert the mass of \( \text{NH}_3 \) to moles using the molar mass of \( \text{NH}_3 \).
2. Use the stoichiometry of the reaction to find moles of \( \text{H}_2 \).
3. Convert the moles of \( \text{H}_2 \) to grams using the molar mass of \( \text{H}_2 \).

This concept is essential in stoichiometry for converting between masses of reactants and products in chemical reactions.
Transcribed Image Text:**Question on Chemical Reaction:** How many grams of \( \text{H}_2 \) can be formed from 87.2 grams of \( \text{NH}_3 \) in the following reaction? \[ 2 \, \text{NH}_3(g) \rightarrow 3 \, \text{H}_2(g) + \text{N}_2(g) \] **Explanation:** This equation represents a chemical reaction where ammonia (\( \text{NH}_3 \)) decomposes to form hydrogen gas (\( \text{H}_2 \)) and nitrogen gas (\( \text{N}_2 \)). The coefficients indicate the molar ratios of the reactants and products: - 2 moles of \( \text{NH}_3 \) produce 3 moles of \( \text{H}_2 \) and 1 mole of \( \text{N}_2 \). To determine the amount of \( \text{H}_2 \) formed from a given mass of \( \text{NH}_3 \), follow these general steps: 1. Convert the mass of \( \text{NH}_3 \) to moles using the molar mass of \( \text{NH}_3 \). 2. Use the stoichiometry of the reaction to find moles of \( \text{H}_2 \). 3. Convert the moles of \( \text{H}_2 \) to grams using the molar mass of \( \text{H}_2 \). This concept is essential in stoichiometry for converting between masses of reactants and products in chemical reactions.
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