How many grams of H2 can be formed from 87.2 grams of NH3 in the following reaction? 2 NH3(g) 3 H2 (g) + N2 (g)

How many moles of NO₂ would be required to produce 3.34 moles of HNO₃ in the presence of excess water in the following chemical reaction? 3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

For every one molecule of NaHCO3(s) there is one molecule of CO2(g) that forms:  NaHCO3(s) + CH3CO2H(aq) --> CO2(g) + H2O(l) + NaCH3CO2(aq) This means that if we know how many moles of gas we need, we need the same number of moles of sodium bicarbonate to produce it. Now, we need something to fill with gas. I'll be filling a 1-quart sealable plastic bag. 1 quart is 946 mL (0.946 L). We can use the ideal gas law to determine how much gas (in moles) is needed to fill 946 mL. Remember there are four variables for the ideal gas law. Ideal Gas Law:    PV = nRT P = pressure: typically 715 mm Hg in Spokane  <-- unit dictates which R to use V = volume: 1 quart bag = 0.946 L   <-- must be in Liters T = room temperature: 20 °C in my lab, +273 = 293 K <-- must be Kelvin n = moles: what we are solving for I used atmospheric pressure in mm Hg, so I'll have to pick the R value with "mm Hg" in the units: R = 62.4 L × m m H g K × m o l Now, use these values to calculate how many moles of…

Predict the products of the reaction below. That is, complete the right-hand side of the chemical equation. Be sure your equation is balanced and contains state symbols after every reactant and product. HCIO (aq) + H2O(l) → ローロ Х 5 2 00 Ar