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How many grams of C a3(PO4)2 (MW = 310.18 g Ca3(PO4)2) are in 2.00E23 molecules of C a3(PO4)2?(Express as "g C a3(PO4)2") 2.00E23 molecules Ca3(PO4)2×1._2._=103 g Ca3(PO4)2 2.00E23 molecules C a 3 (P O4)2 times (1._ over 2._) = 103 g C a3 (P O4) 2

How many grams of C a3(PO4)2 (MW = 310.18 g Ca3(PO4)2) are in 2.00E23 molecules of C a3(PO4)2?(Express as "g C a3(PO4)2") 2.00E23 molecules Ca3(PO4)2×1._2._=103 g Ca3(PO4)2 2.00E23 molecules C a 3 (P O4)2 times (1._ over 2._) = 103 g C a3 (P O4) 2

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How many grams of C a3(PO4)2 (MW = 310.18 g Ca3(PO4)2) are in 2.00E23 molecules of C a3(PO4)2?(Express as "g C a3(PO4)2")

2.00E23 molecules Ca3(PO4)2×1._2._=103 g Ca3(PO4)2

2.00E23 molecules C a 3 (P O4)2 times (1._ over 2._) = 103 g C a3 (P O4) 2

Question 9 4110points How many grams of C az(PO), (MW = 310.18 g Ca3(PO4)2) are in 2.00E23 molecules of C ag(PO4)2?(Express as "g C a3(PO4)2") 2. 00E23 molecules Ca3(PO4)2 x 1. 103 g Ca3 (PO4)2 2.00E23 molecules C a 3 (P 04)2 times (1. over 2. ) = 103 g Ca3 (P O4) 2 %3D 3 6.022E23 molecules Ca3(PO4)2 3 1g Ca3(P04)2 1. 1. 1 1 molecule Ca3(PO4)2 2. 2. 2. 310.18 g Ca3(PO4)2 3. 3 Unused answer 3 1 mole Ca3(P04)2
Transcribed Image Text:Question 9 4110points How many grams of C az(PO), (MW = 310.18 g Ca3(PO4)2) are in 2.00E23 molecules of C ag(PO4)2?(Express as "g C a3(PO4)2") 2. 00E23 molecules Ca3(PO4)2 x 1. 103 g Ca3 (PO4)2 2.00E23 molecules C a 3 (P 04)2 times (1. over 2. ) = 103 g Ca3 (P O4) 2 %3D 3 6.022E23 molecules Ca3(PO4)2 3 1g Ca3(P04)2 1. 1. 1 1 molecule Ca3(PO4)2 2. 2. 2. 310.18 g Ca3(PO4)2 3. 3 Unused answer 3 1 mole Ca3(P04)2
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