How many errors in a message may be detected simultaneously by a single parity bit?

Using parity bits, how many mistakes can be found in a message?

Please help with the following question: If an error is detected with a parity bit, is it possible to correct it? Why or why not?

Consider the example below that shows both the payload and the two- dimensional parity bits (shown in green), and where exactly one of the payload or parity bits shown has been corrupted. In this example, odd parity is used. - 11000100 001111000 01010010010101101 00110111 100011001 11110110011011111 10111011 110011100 00010011 100110000 Please indicate the row and the column location of the bit that has flipped from its original value.

One way of detecting errors is to transmit data as a block of n rows of k bits per row and adding parity bits to each row and each column. The lower-right corner is a parity bit that checks its row and its column, Will this scheme detect all single errors? Double errors? Triple errors?

In a message, how many possible parity bits may be found?

Use the hexadecimal notation to represent the following bit patterns: 1. 0110101011110010, 2. 111010000101010100010111, and 01001000

Would you expect that the inclusion of a parity bit with each character would change the probability of receiving a correct message?

When bit stuffing is used, is it possible for the loss, insertion, or modification of a single bit to cause an error not detected by the checksum? If not, why not? If so, how? Does the checksum length play a role here? Please elaborate the Answer ?