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How many computers? In a simple random sample of 155 households, the sample mean number of personal computers was 1.78. Assume the population standard deviation is o= 0.27. Part: 0 / 4 Part 1 of 4 (a) Construct a 99% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. A 99% confidence interval for the mean number of personal computers is <με Part: 1/4 Part 2 of 4 (b) If the sample size were 175 rather than 155, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) ▼ since (Choose one) in the sample size will (Choose one) ▼ the standard error. Part: 2/4 Part 3 of 4 The margin of error would be (Choose one) ▼ since (Choose one) in the confidence level will (Choose one) the critical value zα/2. X (c) If the confidence levels were 95% rather than 99%, would the margin of error be larger or smaller than the result in part (a)? Explain. Part: 3/4 Part 4 of 4 X X (d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is less than 1? It (Choose one) likely that the mean number of personal computers is less than 1. X

How many computers? In a simple random sample of 155 households, the sample mean number of personal computers was 1.78. Assume the population standard deviation is o= 0.27. Part: 0 / 4 Part 1 of 4 (a) Construct a 99% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. A 99% confidence interval for the mean number of personal computers is <με Part: 1/4 Part 2 of 4 (b) If the sample size were 175 rather than 155, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) ▼ since (Choose one) in the sample size will (Choose one) ▼ the standard error. Part: 2/4 Part 3 of 4 The margin of error would be (Choose one) ▼ since (Choose one) in the confidence level will (Choose one) the critical value zα/2. X (c) If the confidence levels were 95% rather than 99%, would the margin of error be larger or smaller than the result in part (a)? Explain. Part: 3/4 Part 4 of 4 X X (d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is less than 1? It (Choose one) likely that the mean number of personal computers is less than 1. X

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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How many computers? In a simple random sample of 155 households, the sample mean number of personal computers was 1.78. Assume the population standard deviation is o = 0.27. Part: 0 / 4 Part 1 of 4 (a) Construct a 99% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. A 99% confidence interval for the mean number of personal computers is <μ< Part: 1 / 4 Part 2 of 4 The margin of error would be (Choose one) size will (Choose one) the standard error. (b) If the sample size were 175 rather than 155, would the margin of error be larger or smaller than the result in part (a)? Explain. Part: 2 / 4 Part 3 of 4 The margin of error would be (Choose one) since (Choose one) in the confidence level will (Choose one) the critical value z a/2* Part: 3 / 4 since (Choose one) in the sample (c) If the confidence levels were 95% rather than 99%, would the margin of error be larger or smaller than the result in part (a)? Explain. Part 4 of 4 X I Ś X X Ś (d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is less than 1 ? It (Choose one) likely that the mean number of personal computers is less than 1. S Es
Transcribed Image Text:How many computers? In a simple random sample of 155 households, the sample mean number of personal computers was 1.78. Assume the population standard deviation is o = 0.27. Part: 0 / 4 Part 1 of 4 (a) Construct a 99% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. A 99% confidence interval for the mean number of personal computers is <μ< Part: 1 / 4 Part 2 of 4 The margin of error would be (Choose one) size will (Choose one) the standard error. (b) If the sample size were 175 rather than 155, would the margin of error be larger or smaller than the result in part (a)? Explain. Part: 2 / 4 Part 3 of 4 The margin of error would be (Choose one) since (Choose one) in the confidence level will (Choose one) the critical value z a/2* Part: 3 / 4 since (Choose one) in the sample (c) If the confidence levels were 95% rather than 99%, would the margin of error be larger or smaller than the result in part (a)? Explain. Part 4 of 4 X I Ś X X Ś (d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is less than 1 ? It (Choose one) likely that the mean number of personal computers is less than 1. S Es
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