How does Sb2(S O4)5(s) break up in solution? Write subscripts and superscripts as normal numbers and do not include spaces in your answer. Do not include states like (aq) or "1" in front of single atoms or charges. For example, the answer for NiCl3(s) would be Ni3++3Cl-  For example, the answer for Sb3(PO4)5(s) would be 3Sb5++5PO43-  Possibly relevant polyatomic ions: CN-,OH-, NO3-, NO2-, ClO3-, ClO4-, CO32-, SO42-, CrO42-, Cr2O72-, PO43-, PO33-

How does Sb₂(S O₄)_5(s) break up in solution? Write subscripts and superscripts as normal numbers and do not include spaces in your answer. Do not include states like (aq) or "1" in front of single atoms or charges.

For example, the answer for NiCl_3(s) would be Ni3++3Cl- 

For example, the answer for Sb₃(PO₄)_5(s) would be 3Sb5++5PO43- 

Possibly relevant polyatomic ions:

CN^-,OH^-, NO₃^-, NO₂^-, ClO₃^-, ClO₄^-,

CO₃^2-, SO₄^2-, CrO₄^2-, Cr₂O₇^2-,

PO₄^3-, PO₃^3-

Screen Reader User: For example, the answer for NiCl_3(s) would be Ni3++3Cl minus 

For example, the answer for Sb₃(P O₄)_5(s) would be 3Sb5++5PO43 minus 

Possibly relevant polyatomic ions:

CN ^minus,O H ^minus, N O₃ ^{1 minus}, N O₂ ^{1 minus}, Cl O₃ ^{1 minus}, Cl O₄ ^{1 minus},

C O₃ ^{2 minus}, S O₄ ^{2 minus}, Cr O₄ ^{2 minus}, Cr₂ O₇ ^{2 minus},

P O₄ ^{3 minus}, P O₃ ^{3 minus}