In question 1 can you explain part b I don’t understand how the moment of inertia was deduced then on the right it becomes negative and the R becomes squared please explain this Problem 1-Friction, pulley, and dragTA(a) Fr"Bfree-body diagramsImsgWhen the system is at rest, the pulley does notrotate and TA=TB = TFor object AFor object BThere for:MA max(b) MB/MA=7m₂ = m₂Aкрутв=F = T ≤ Ffr, max = M₂MAgT = mB9<m3g = us mag0.5us2 (MB/MA) max1.0For the pulley: (TB-TA) R = Iα = Ia/RFor object A:TA-MK mag.= MA aFor object B.and so: (m_MA = MB)TA-MK mag + mag-/B = (MA+MB) 2- Ia/R² + (1-μk) mg = 2m ²I= _ 2 m² = (1-4₂) ma2/R²mR² -[(1-₂) 2 -2]m = 1 kg; R = 0.1m; 2= 19, 1=0.42I = MR² [0.6-5-2] - MR² = 1x10 " kgm²=(C) With drag:dvтвdtтв д-Тве тва= mBg - T₂ - bv;MBg-TB = M₁₂ 2V₁ =mg5 bthereforemgb= = = 0.25VT Problem 1- Friction, pulley, and dragA system is composed of two masses connected by a massless cord going through a pulley, as shown in the figure. Object A,with mass ma, lies on a horizontal plane, with coefficient of static friction = 0.5 and kinetic friction μ = 0.4. Object B, withmass me=1.0 kg, is suspended in air. The pulley is basically a cylinder with radius R = 0.1 m. (a) Draw free-body diagrams forthe two masses and for the pulley. Find the maximum value of the mass ratio, (mB/MA)max, such that, for ma/mA<(MB/MA)max,the system stays at rest. (b) Assume now that mB/MA= 2(MB/MA)max and that object B falls with initial acceleration a=g/5. Findthe value of the moment of inertia of the pulley and of the tension force TB exerted on object B. (c) For the same parametersand values of Te obtained (b), suppose that object B is also acted upon by a drag force Fo=-bv, and that the object is allowedto fall attached to the string until it reaches a constant terminal velocity, Vr= 9.8 m/s; find the value of the drag coefficient, b.

Name: In question 1 can you explain part b I don’t understand how the moment
Uploaded: 2024-03-20T06:57:37.000Z
Channel: Bartleby
Description: In question 1 can you explain part b I don’t understand how the moment of inertia was deduced then on the right it becomes negative and the R becomes squared please explain this Problem 1-Friction, pulley, and dragTA(a) Fr"Bfree-body diagramsImsgWhen