Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Question
How did they draw root locus? P=2? And how they get the breakpoint?
(b)
S(s+1)
G(6)
Root locas Branch P>>2
と=o
P= 2
S=0
fii) Break point
ヒー。
CE = 1+k
s(st1)
4.
dk
dk
=>
(25+1)=0
%3D
d6
Breakpoint e
2.
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Transcribed Image Text:(b) S(s+1) G(6) Root locas Branch P>>2 と=o P= 2 S=0 fii) Break point ヒー。 CE = 1+k s(st1) 4. dk dk => (25+1)=0 %3D d6 Breakpoint e 2.
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