Hot air at 1 bar and 80 degree Celcius enters a 8 m long uninsulated square duct of cross-section 20 cm x 20 cm that passes through the attic of a house at a rate of 150 L/s. The duct is observed to be constant surface temperature of 60 degrees Celcius. Determine (a) air film coefficient (b) the exit temperature of air (c) logarithmic mean temperature difference (d) the rate of heat loss from the duct to the attic space. From Table A-18, for air gives, density, ρ = 1.009 kg/m^3 thermal conductivity, k = 0.0297 W/m degree celcius viscosity, v = 2.06 x 10^-5 m^2/s specific heat, Cp = 1008 J/kg degree celcius Prandtl no., Pr = 0.706
Hot air at 1 bar and 80 degree Celcius enters a 8 m long uninsulated square duct of cross-section 20 cm x 20 cm that passes through the attic of a house at a rate of 150 L/s. The duct is observed to be constant surface temperature of 60 degrees Celcius. Determine (a) air film coefficient (b) the exit temperature of air (c) logarithmic mean temperature difference (d) the rate of heat loss from the duct to the attic space. From Table A-18, for air gives, density, ρ = 1.009 kg/m^3 thermal conductivity, k = 0.0297 W/m degree celcius viscosity, v = 2.06 x 10^-5 m^2/s specific heat, Cp = 1008 J/kg degree celcius Prandtl no., Pr = 0.706
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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- Hot air at 1 bar and 80 degree Celcius enters a 8 m long uninsulated square duct of cross-section 20 cm x 20 cm that passes through the attic of a house at a rate of 150 L/s. The duct is observed to be constant surface temperature of 60 degrees Celcius. Determine (a) air film coefficient (b) the exit temperature of air (c) logarithmic mean temperature difference (d) the rate of heat loss from the duct to the attic space.
From Table A-18, for air gives,
density, ρ = 1.009 kg/m^3
thermal conductivity, k = 0.0297 W/m degree celcius
viscosity, v = 2.06 x 10^-5 m^2/s
specific heat, Cp = 1008 J/kg degree celcius
Prandtl no., Pr = 0.706
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