Horizontal CurveGiven:Radius (R) = 1654.35'Degree of Curve (Daº) = 03°-27¹-48"PC Station = 14 + 27.62Chord distance to Station 16 +00= ?172.30'170.10'174.59'168.75'

A Curve is given. Radius, R = 1654.35' Degree of the curve, D = 3°27'48'' PC station = 14 + 27.62 To determine chord distance to station 16+00 Steps First, determine the length of the arc Then, the angle of deflection Finally, use formula for length of the chordThe length of the curve between PC and 16+00, lc lc = 16+00-14+27.62=1600-1427.62=172.38' The length of the arc is 172.38' Now, from the chord definition lc=πR180×2δδ is deflection angle172.38 = π×1654.35180×2δδ = 2°59'6.19'' Finally, The chord length = 2Rsin2δ=2×1654.35×sin2°59'6.19''=172.30' Thus, the chord length between station PC and 16+00 station is 172.30' The chord length between station PC and 16+00 station is 172.30'. Thus, the first option is correct.

Answered: Horizontal Curve Given: Radius (R) =…

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Civil Engineering

Horizontal Curve Given: Radius (R) = 1654.35' Degree of Curve (Daº) = 03°-27'-48" PC Station = 14 + 27.62 Chord distance to Station 16 + 00 = ? 172.30' 170.10' 174.59' 168.75'

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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