How can I do this 22. Some emojis have teeth that they show off then they smile and some do pene emoji is famous for his big, toothy grin, but his wife is toothless. If Buck isnomozygous for his teeth, what gre the chances of passing on his toothy smile to theorrspring? Create a Punnett square and write the probabilities on the lines below.Has teethNo teeth23. We know that emojis can either have eyes that are open or closed, but somepecial emojis have the ability to winkl Winking is a recessive trait represented by theletter "w." Write all of the different phenotypes and genotypes for winkers and non-winkers and then create a Punnett Square to show the probability of two emojis wriodre heterozygous for this gene having offspring who are able to wink.PhenotypesGenotypesWinkersNon-winkers.24. Sleepy the emoji was always self-conscious of her olosed eyes and she fell in lovewith a handsome, open-eyed emoji dude, but she wasn't sure if he was homozygous orheterozygous for his open eyes. Their first child had open eyes, but their second hadclosed eyes. What genotype did emoji dude have? Create two Punnett Squares and) explain how you know his genotype using evidence from your squares.25. In the space to the right, draw anemoji using the three traits listed onour chart. Underneath your emoji,write the genotypes and phenotypesfor each trait that your emoji has.©Schilly Science

Teeth is encoded by single gene. The single gene has two alleles. T and t are two alleles of a…

homozygous for his teeth, what are the chances of passing on his toothy smile to thor 22. Some emojis have teeth that they show off then they smile and some do no he emoji is famous for his big, toothy grin, but his wife is toothless. If Buck is orrspring? OCreate a Punnett square and write the probabilities on the lines below. Has teeth No teeth

homozygous for his teeth, what are the chances of passing on his toothy smile to thor 22. Some emojis have teeth that they show off then they smile and some do no he emoji is famous for his big, toothy grin, but his wife is toothless. If Buck is orrspring? OCreate a Punnett square and write the probabilities on the lines below. Has teeth No teeth

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter41: Animal Reproductive System

Section: Chapter Questions

Problem 4DAA

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non OBYTOT SEI deutet bos nuol 3. Based on the total number of kernels of corn you counted, calculate the expected number for each phenotype if the parents of this corn were both RrTt. Show how you calculate these numbers below and en transfer them to the observation table (155 Kernels) then INO 4 4. Using chi-square analysis to compare the actual phenotype and expected phenotype numbers determine if you can statistically accept that both parents have the genotype RrTt. Your chi square data will be recorded to helow. nb number) which allows for
1. Both parents are homozygous for the allele for myostatin that results in typical muscles (mm x mm). a. Part A (fill in the boxes): m m m 12 b. Part B (fill in the boxes): Total number of offspring with the heavily muscled phenotype Proportion and percent of heavily muscled offspring Total number of offspring with the in-between phenotype Proportion and percent of in-between offspring Total number of offspring with typical muscles Proportion and percent of typical muscled offspring Total: 100%
2. Describe the phenotype of the cats with these genotypes (If allele not specified, assume wild type): CC ss OO BB dd McMc tt ww Light brown male with choco [Choose ] Light brown male with chocolate tips ctct ss OY bb TAt A uniformly colored black cat Light grey female with dark grey mackerel stripes Black female with large white patches Dark grey with black mackerel stripes Cc SS Oo BB TATA Cream male with small white patches and orange mackerel stripes CC Ss oY bb dd tt [Choose ]
A single allele gives rise to the Hbs form of hemoglobin. Individuals who are homozygous for the allele (HbS/HbS) develop sickle-cell anemia (Section 9.6). Heterozygous individuals (HbA/HbS) have few symptoms. A couple who are both heterozygous for the HbS allele plan to have children. For each of the pregnancies, state the probability that they will have a child who is: a. homozygous for the HbS allele b. homozygous for the normal allele (HbA) c. heterozygous: HbA/HbS
In sweet pea plants, an allele for purple flowers. (P) is dominanl when paired with a recessive allele for red flowers (p). An allele for Jang pollen grains (L) is dominant when paired with a recessive allele for round pollen grains (L). Bateson and Punnett crossed a plant having purple flowers and long pollen grains with one having white flowers and round pollen grains. All F1 offspring have purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple /lower/ round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?
For each genotype listed, what allele combinations will occur in gametes? a. AABBCC b. AaBBc c. AaBBcc d. AaBbCc
Figure 19.2 In plants, violet flower color (V) is dominant over white (v). If p = .8 and q = 0.2 in a population of 500 plants, how many individuals would you expect to be homozygous dominant (VV), heterozygous (Vv), and homozygous recessive (vv)? How many plants would you expect to have violet flowers, and how many would have white flowers?
A wild population of pea plants has two alleles for flower color in its gene pool. A dominant allele (P) specifies purple flowers; a recessive allele (p) specifies white flowers. If the die frequency of allele P is 0.75, what is the expected frequency of allele p?
Explain how having a heterozygous genotype for sickle-cell in Malaria stricken areas of Africa is a benefit. v 3 (12pt) Arial TTTT Paragraph v T T, OM HTHL CSS O S Mashups- Path: p ост 28 MacBook Air 80 esc F1 F2 F3 F4 F5 F6 F7 @ #3 $4 & 1 2 3 4 6. 7 8. Q W R Y U A S F J lock C V N control option command エ D N ピ
Im pP x PP 6/6 wa s hatarosygous genotypa? Dark eyes Dark eyes 11. What percentage of the offspring will have a heterozygous genotype? 12. What will the ratio of flies with dark eyes to white eyes be? Dd x x Dd 13. What percentage of the offspring will be short? Tall Tall 14. What percentage of the offspring will have a homozygous dominant genotype? TT х Tt 15. What percentage of the offspring will Long beak Long beak have long beaks?
A A EE v E v E E 12 Aa v AaBbCcDdE AaBb AaBbCcDdEe AaBbCcDdEe AaBbCcD ab x, х, х* x A evAv Normal No Spacing Heading 1 Heading 2 Title Styles Pane Dicta Q4. Assume eye colour in humans is controlled by a pair of alleles of a gene where the allele giving brown eyes is dominant to the allele giving blue eyes. Both parents of a blue-eyed man, John, were brown-eyed. He married a brown-eyed woman, Sara, whose father had brown eyes and mother blue eyes. Sara had a blue-eyed sister. John and Sara had a brown-eyed child. 1) Fill in the boxes and circles on the family tree below to show the genotype of each individual. John Sara Q5. When Mendel crossed a large number of tall pea plants with short pea plants all E1 plants
D Page view A Read aloud Draw Highlight PRA Can you curl your tongue up on the sides? Tongue-curling in humans is a dominant genetic trait. Suppose a man who is Tt for tongue-curling marries a woman who is also Tt for this trait. What are the possible genotypes and phenotypes of their children and the percent chance for each? 4. 1 Fill in the table: Genotype Phenotype Chance