Homework 12 Problem 5:   A camera with a 110.7-mm focal length lens is being used to photograph the Sun.   What is the image height of the Sun on the film, in millimeters, given the sun is 1.40 × 106 km in diameter and is 1.50 × 108 km away?  hi = ______

HW Q7

An object is 19.5 cm from the center of a spherical silvered-glass Christmas tree ornament 6.20 cm in diameter. ▼ Part A What is the position of its image (counting from the ornament surface)? Follow the sign rules. Express your answer with the appropriate units. s' = Submit ▾ Part B m = HA Value Submit Request Answer What is the magnification of its image? VG ΑΣΦ Units Request Answer PYREX ? ?

2. A convex (converging) lens produces a real, inverted image of an object that is magnified 2.50 times when the object is 19.0 cm from the lens. What is the focal length of the lens? cm

A concave mirror on the left is separated from a converging lens on the right by 50 cm. An object is placed 20.0 cm to the right of a concave mirror with focal length 12.0 cm and 30.0 cm to the left of a converging lens with focal length 10.0 cm, what would be the magnification factor created by both the mirror and lens. 1. do not have enough information to do a calculation 2.one  3.two 4. none of the given choices

A camera lens used for taking close-up photos has a focal length of 11.8 mm. The farthest it can be placed from the film is 41 mm.   What is the closest object that can be photographed in mm?  d0 =  | mm

4. A concave lens has focal length of 27 cm. At what distance from the lens a tall object be placed so that it forms an image at 18 cm from the lens? Answer: b =

A lens with a focal length of 4.00 cm is placed 10.00 cm from an object. The lens described would be a _________ lens. The image described would be  a ________ image. a. converging, real b. converging, virtual c. diverging, virtual d. diverging, real