Hole diameter 8.1/2 inch Hole depth = 13,000 ft Plastic viscosity = 35 cP Yield point = 25 lb / 100 ft² Mud weight = 13 lb/gal Flow rate= 400 gpm Drill pipe ID = 4.276 in / OD = 5 in Drill collars ID=2.875 in / OD = 6.5 in/ Length

Structural Analysis
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Chapter2: Loads On Structures
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The following data for an exploration well of 13,000 ft depth:
Hole diameter = 8.1/2 inch
Hole depth = 13,000 ft
Plastic viscosity = 35 cP
Yield point = 25 lb / 100 ft²
Mud weight = 13 lb / gal
Flow rate = 400 gpm
Drill pipe ID = 4.276 in / OD = 5 in
Drill collars ID = 2.875 in / OD = 6.5 in / Length = 500 ft
Previous casing = 95/8 in / ID = 8.755 in set at 10,000 ft
Pump pressure = 3000 psi
Surface equipment type = 4
1.
According to the above information calculate the following by using the Bingham
plastic model and power-law model.
• The nozzle sizes
• The bottom hole pressure while circulating
2.
Compare and discuss the results. Explain which model is more accurate.
3.
Compare the two models with Hughes charts.
Compare the results of the models and charts with bit hydraulic optimization
software given.
Transcribed Image Text:The following data for an exploration well of 13,000 ft depth: Hole diameter = 8.1/2 inch Hole depth = 13,000 ft Plastic viscosity = 35 cP Yield point = 25 lb / 100 ft² Mud weight = 13 lb / gal Flow rate = 400 gpm Drill pipe ID = 4.276 in / OD = 5 in Drill collars ID = 2.875 in / OD = 6.5 in / Length = 500 ft Previous casing = 95/8 in / ID = 8.755 in set at 10,000 ft Pump pressure = 3000 psi Surface equipment type = 4 1. According to the above information calculate the following by using the Bingham plastic model and power-law model. • The nozzle sizes • The bottom hole pressure while circulating 2. Compare and discuss the results. Explain which model is more accurate. 3. Compare the two models with Hughes charts. Compare the results of the models and charts with bit hydraulic optimization software given.
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