HoiH H₁: H (Type integers or decimals. Do not round.)

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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State the null and alternative hypothesis.

 

H0: ≠, >, =, or <  ____________  (Type an integers or decimals. Do not round) 

 

H1: ≠, >, ≤, <, ≥, or = __________ (Type an integers or decimals. Do not round)

 

 

 
 
 
 
**Educational Content:**

**Hypothesis Testing on Cotinine Levels in Smokers vs. Nonsmokers**

In this study, the claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL, which is found in nonsmokers. Cotinine serves as an important biomarker to measure exposure to nicotine. 

- **Sample Size:** The number of participants in the study is \( n = 778 \).
- **Test Statistic:** The calculated t-value for the hypothesis test is \( t = 58.258 \).

To reach a conclusion, use statistical technology to find the P-value, which will allow for determining if the observed result is statistically significant at the chosen significance level. The significance level (alpha) for this test is \( 0.10 \).

**Task:**
State the null and alternative hypotheses for the study:

- **Null Hypothesis (\( H_0 \)):** 
  - Representation: \(\mu \)
  - Value to compare: 2.84
  - Hypothesis: The mean cotinine level for smokers is equal to 2.84 ng/mL.

- **Alternative Hypothesis (\( H_1 \)):** 
  - Representation: \(\mu \)
  - Value to compare: 2.84
  - Hypothesis: The mean cotinine level for smokers is greater than 2.84 ng/mL.

*(Note: Input either integers or decimals. Avoid rounding values.)*
Transcribed Image Text:**Educational Content:** **Hypothesis Testing on Cotinine Levels in Smokers vs. Nonsmokers** In this study, the claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL, which is found in nonsmokers. Cotinine serves as an important biomarker to measure exposure to nicotine. - **Sample Size:** The number of participants in the study is \( n = 778 \). - **Test Statistic:** The calculated t-value for the hypothesis test is \( t = 58.258 \). To reach a conclusion, use statistical technology to find the P-value, which will allow for determining if the observed result is statistically significant at the chosen significance level. The significance level (alpha) for this test is \( 0.10 \). **Task:** State the null and alternative hypotheses for the study: - **Null Hypothesis (\( H_0 \)):** - Representation: \(\mu \) - Value to compare: 2.84 - Hypothesis: The mean cotinine level for smokers is equal to 2.84 ng/mL. - **Alternative Hypothesis (\( H_1 \)):** - Representation: \(\mu \) - Value to compare: 2.84 - Hypothesis: The mean cotinine level for smokers is greater than 2.84 ng/mL. *(Note: Input either integers or decimals. Avoid rounding values.)*
### Statistical Analysis Exercise:

1. **Test Statistic**: 
   - The test statistic is represented as a blank input field. (Round to two decimal places as needed.)

2. **P-Value**: 
   - The P-value is represented as a blank input field. (Round to three decimal places as needed.)

3. **Interpretation of P-Value**:
   - Based on the P-value, there is a dropdown menu providing options for the sufficiency of evidence.
   - This is followed by another dropdown menu to decide whether to reject or fail to reject the claim.
   - The claim in question is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers.

This exercise requires filling in statistical results to make an inference about cotinine levels in smokers compared to non-smokers.
Transcribed Image Text:### Statistical Analysis Exercise: 1. **Test Statistic**: - The test statistic is represented as a blank input field. (Round to two decimal places as needed.) 2. **P-Value**: - The P-value is represented as a blank input field. (Round to three decimal places as needed.) 3. **Interpretation of P-Value**: - Based on the P-value, there is a dropdown menu providing options for the sufficiency of evidence. - This is followed by another dropdown menu to decide whether to reject or fail to reject the claim. - The claim in question is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. This exercise requires filling in statistical results to make an inference about cotinine levels in smokers compared to non-smokers.
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