Hii, I asked this question but may I ask how to get 1.1547? thank you 5:43←ANSWEREDFriday, Nov 11, 2022ENGINEERING MECHANICAL-ENGINEERINGGiven the trust below and a force P applieddownwards at Point D, determinethe member forces EC and CD using Methodof Jointsurgentt thank youExpert AnswerStep1a)Given:A force P applied downward- To Find: The memberforcesof iniute?atEC & CD√xpoint DusingDO8 5:43个Step2b)- Draw> Solution: Using MethodCD c0560'EDDrawBCCE Singo' 4ECCD + CD Sin60ECC0168Answers:D4360'PCB43FBD of joint D.+CDCOS 60'CD Sin60CDMemberEc43FBD of joint c.4320of joints.434CForce(1.1547) P(1.1547) P60IF 20CD sin 60DP(++);== P+ CD = (1.1547) P (Tension)EF co co +),EC sin 60 = CD sin60"EC = CD"EC = (1-1547) P [Compression)NatureofForceTensionCompression,Was this solution√xDO

In this problem, it is asking how to get 1.1547 in the given calculations.

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Engineering

Mechanical Engineering

Hii, I asked this question but may I ask how to get 1.1547? thank you

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Thermal Properties of Materials

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Hii, I asked this question but may I ask how to get 1.1547? thank you

5:43
←
ANSWERED
Friday, Nov 11, 2022
ENGINEERING MECHANICAL-ENGINEERING
Given the trust below and a force P applied
downwards at Point D, determine
the member forces EC and CD using Method
of Joints
urgentt thank you
Expert Answer
Step1
a)
Given:
A force P applied downward
- To Find: The member
forces
of iniute
?
at
EC & CD
√x
point D
using
DO
8

5:43
个
Step2
b)
- Draw
> Solution: Using Method
CD c0560'
ED
Draw
BC
CE Singo' 4
EC
CD + CD Sin60
ECC0168
Answers:
D
43
60'
P
C
B
43
FBD of joint D.
+
CDCOS 60'
CD Sin60
CD
Member
Ec
43
FBD of joint c.
43
20
of joints.
43
4
C
Force
(1.1547) P
(1.1547) P
60
IF 20
CD sin 60
D
P
(++);
=
= P
+ CD = (1.1547) P (Tension)
EF co co +),
EC sin 60 = CD sin60"
EC = CD
"EC = (1-1547) P [Compression)
Nature
of
Force
Tension
Compression,
Was this solution
√x
DO

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