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College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A high power line carries a current of 4.7 kA. What is the strength of the magnetic field this line produces at the ground, 3.84 m away? (μ0 = 4π × 10-7 T ∙ m/A). Express your answer in milliTeslas.
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- An electron is moving with an initial velocity of 7.09 x 10° m/s through a magnetic field. If the angle at which the electron is cutting through the magnetic field (0) is 33.9° and the force acting on the electron is 2.89 x 1014 N, then what is the strength of the magnetic field in tesla? Your Answer: Answerarrow_forwardA magnetic field directed into the page changes with time according to B = 0.037 ot² + 1.40, where B is in teslas and t is in seconds. The field has a circular cross section of radius R = 2.50 cm (see figure below). xxxxx xxxxx ****** * I xxx 1 19/ x Rx xxxxx х х xxxxxx x xxxxx Bin P₁ (a) When t = 4.20 s and r₂ = 0.020 0 m, what is the magnitude of the electric field at point P₂? N/C (b) When t = 4.20 s and r₂ = 0.020 0 m, what is the direction of the electric field at point P2? O perpendicular to r₂ and counterclockwise O into the page O perpendicular to r₂ and clockwise O out of the pagearrow_forward005 A long, thin conductor carries a current of 9.24 A. At what distance from the conductor is the magnitude of the resulting magnetic field 0.000153 T? Answer in units of cm.arrow_forward
- A magnetic field has a magnitude of 0.0527 T and is uniform over a circular surface whose radius is 0.226 m. The field is oriented at an angle of 27.9o with respect to the normal to the surface. What is the magnetic flux through the surface?arrow_forwardCertain experiments must be performed in the absence of any magnetic fields. Suppose such an experiment is located at the center of a large solenoid oriented so that a current of I = 3.40 A produces a magnetic field that exactly cancels Earth's 4.50 x 10-5 T magnetic field. Find the solenoid's number of turns per meter. HINT turns/marrow_forwardA magnetic field directed into the page changes with time according to B = 0.031 ot² + 1.40, where B is in teslas and t is in seconds. The field has a circular cross section of radius R = 2.50 cm (see figure below). xxxx vPg xxx xxx xxxx x Rx Bin P₁ (a) When t = 4.80 s and r₂ = 0.020 0 m, what is the magnitude of the electric field at point P₂? 0.00030 X Your response is off by a multiple of ten. N/C (b) When t = 4.80 s and r₂ = 0.020 0 m, what is the direction of the electric field at point P₂? perpendicular to r₂ and counterclockwise O into the page O out of the page. O perpendicular to ₂ and clockwisearrow_forward
- 5. Once more, please refer to the figure. This time the charge is 7.98 x 10^-6 C, the magnetic field strength is 2.68 T and the electric field strength is 1.70 x 10^5 N/C. The charge experiences a total force of magnitude 15.00 N as it enters the region. What is its speed as it enters the region? 1.08E+06 m/s 6.38E+05 m/s 4.47E+05 m/s 9.57E+05 m/sarrow_forwardAn electron ( me = 9.11x1031 kg. q=1.6x10-91 C) moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 7.3 mT. If the speed of the electron is 1.50 x107 m/s, determine the radius of the circular path ( in units of cm). Select one: A. 0.62 B. 1.17 С. 1.72 D. 1.44 E. 0.04arrow_forward
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