Att = 0, force F-=(6.30i +6.10j +3.50k)N begins to act on a 2.90 kg particle with an initial speed of 3.60 m/s. What is the particle's speed when its displacement from the initial point is d = (1.60î + 2.80j + 7.80k) m ?

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Q: Att = 0, force F (- 3.80i + 5.20j + 3.10k ) N begins to act on a 2.90 kg particle with an initial…

A: F→ = -3.80i^ + 5.20j^ + 3.10k^ N d→ = 1.80i^ + 2.10j^ + 6.90k^ m m = 2.90 kg vi = 3.60 m/s vf = ?

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