hi can you explain why the integral is from 0 to pie/2 and 0 to 2 pie Example (page 181)If J = - (2 cos 0 a, + sin 0 a,) A/m², calculate the current passing through(a) A hemispherical shell of radius 20 cm(b) A spherical shell of radius 10 cmExample (page 181)Solution:1- JJ. ds. where dS = r²sin 9 do de a, in this case.w/22m(a) I = = [2 / 2 cos 0 r² sine døp de0=0-6=0ra/2-32=*sindsin).sin 0 d( sin 0)6=047 sin² 00.2 2 10== 107 = 31.4 ATr=0.2

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hi can you explain why the integral is from 0 to pie/2 and 0 to 2 pie

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter19: Capacitors

Section: Chapter Questions

Problem 3RQ: A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted...

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Wheatstone Bridge Method

A Wheatstone bridge is a circuit used to measure unknown resistance by measuring the ratios of the two branches of the circuit such that each branch has two resistance and out of four resistance one is unknown. The two branches are joined in between with the help of galvanometer which is used to determine the direction of the current. The main advantage of this circuit is that it can provide the most accurate measurement (different from a simple voltage separator).

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hi can you explain why the integral is from 0 to pie/2 and 0 to 2 pie

Example (page 181)
If J = - (2 cos 0 a, + sin 0 a,) A/m², calculate the current passing through
(a) A hemispherical shell of radius 20 cm
(b) A spherical shell of radius 10 cm
Example (page 181)
Solution:
1- JJ. ds. where dS = r²sin 9 do de a, in this case.
w/22m
(a) I = = [2 / 2 cos 0 r² sine døp de
0=0-6=0
ra/2
-32=
*sindsin).
sin 0 d( sin 0)
6=0
47 sin² 0
0.2 2 10
=
= 107 = 31.4 A
Tr=0.2

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