Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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What is the balanced equation for this reaction (in lowest multiple integers)?

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**H₂(g) + I₂(s) → 2HI(g)**

1. **Mass of HI Produced**

   Given an initial mass of 17.8 g H₂, an excess of I₂, and assuming that all of the reactant is converted to product(s), and none is lost, calculate the mass (g) of HI produced by the reaction.

   **Input:**
   - Enter mass in grams (g): [Input box]

   **Action:**
   - Submit [Button]

2. **Mass of H₂ Consumed**

   Determine the mass (g) of the reactant, H₂, consumed by the reaction.

   **Input:**
   - Enter mass in grams (g): [Input box]

   **Action:**
   - Submit [Button]

3. **Moles of H₂ Consumed**

   The entire mass, 17.8 g, of the reactant H₂ is consumed by the reaction. Calculate the amount (mol) of H₂ in this mass.

   **Molar mass = 2.02 g/mol**

   **Input:**
   - Enter amount in moles (mol): [Input box]

   **Action:**
   - Submit [Button]

4. **Moles of HI Formed**

   Given that 8.8294 mol H₂ was consumed, calculate the amount of HI formed.

   **Input:**
   - Enter amount in moles (mol): [Input box]

   **Action:**
   - Submit [Button]

5. **Mass of HI Formed**

   Complete consumption of H₂ yields 17.6587 mol of HI. Calculate the mass of this quantity of HI.

   **Molar mass = 127.91 g/mol**

   **Input:**
   - Enter mass in grams (g): [Input box]

   **Action:**
   - Submit [Button]

--- 

This transcription elaborates on the chemical reaction process, guiding students through calculations involving mass and mole conversions within this specific chemical context.
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Transcribed Image Text:--- **H₂(g) + I₂(s) → 2HI(g)** 1. **Mass of HI Produced** Given an initial mass of 17.8 g H₂, an excess of I₂, and assuming that all of the reactant is converted to product(s), and none is lost, calculate the mass (g) of HI produced by the reaction. **Input:** - Enter mass in grams (g): [Input box] **Action:** - Submit [Button] 2. **Mass of H₂ Consumed** Determine the mass (g) of the reactant, H₂, consumed by the reaction. **Input:** - Enter mass in grams (g): [Input box] **Action:** - Submit [Button] 3. **Moles of H₂ Consumed** The entire mass, 17.8 g, of the reactant H₂ is consumed by the reaction. Calculate the amount (mol) of H₂ in this mass. **Molar mass = 2.02 g/mol** **Input:** - Enter amount in moles (mol): [Input box] **Action:** - Submit [Button] 4. **Moles of HI Formed** Given that 8.8294 mol H₂ was consumed, calculate the amount of HI formed. **Input:** - Enter amount in moles (mol): [Input box] **Action:** - Submit [Button] 5. **Mass of HI Formed** Complete consumption of H₂ yields 17.6587 mol of HI. Calculate the mass of this quantity of HI. **Molar mass = 127.91 g/mol** **Input:** - Enter mass in grams (g): [Input box] **Action:** - Submit [Button] --- This transcription elaborates on the chemical reaction process, guiding students through calculations involving mass and mole conversions within this specific chemical context.
**Chemical Reaction Worksheets**

**1. Balancing Chemical Equations:**
   - **Reaction:** \( \_\_\_ \text{MnO}_2(s) + \_\_\_ \text{Al}(s) \rightarrow \_\_\_ \text{Mn}(s) + \_\_\_ \text{Al}_2\text{O}_3(s) \)
   - *Enter the balanced equation in lowest multiple integers.*

**2. Stoichiometry Calculations:**

   a. **Calculating Moles of MnO₂:**
   - *Question:* How many moles are present in 53.9 g of MnO₂?
   - *Enter moles of MnO₂:*

   b. **Mole Ratio Determination:**
   - **Reaction:** \( 3 \text{MnO}_2(s) + 4 \text{Al}(s) \rightarrow 3 \text{Mn}(s) + 2 \text{Al}_2\text{O}_3(s) \)
   - *Enter the mole ratio of Al to MnO₂:*

   c. **Reacting Moles of Al:**
   - *Question:* How many moles of Al are required to completely react with 0.620 mol MnO₂?
   - *Enter moles of Al:*

   d. **Mass of Al Required:**
   - *Question:* What is the mass of Al required?
   - *Enter mass of Al in grams:*

   e. **Formation of Iron(III) Chloride:**
   - **Reaction:** \( \text{Fe}(s) + \text{Cl}_2(g) \rightarrow \text{FeCl}_3(s) \)
   - *Question:* How many milligrams of iron(III) chloride result when 20.00 mg of iron is reacted with excess chlorine gas?
   - *Enter mass in mg of FeCl₃:*

**3. Limiting Reagent Analysis:**

   a. **Amount of Acetic Acid Formed:**
   - *Question:* What amount of HC₂H₃O₂ can be formed from the amount of each reactant?
     - If all of the CH₃CHO was used up in the reaction, how many moles of HC₂H₃O₂ would be produced?
     - *Enter moles of HC₂
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Transcribed Image Text:**Chemical Reaction Worksheets** **1. Balancing Chemical Equations:** - **Reaction:** \( \_\_\_ \text{MnO}_2(s) + \_\_\_ \text{Al}(s) \rightarrow \_\_\_ \text{Mn}(s) + \_\_\_ \text{Al}_2\text{O}_3(s) \) - *Enter the balanced equation in lowest multiple integers.* **2. Stoichiometry Calculations:** a. **Calculating Moles of MnO₂:** - *Question:* How many moles are present in 53.9 g of MnO₂? - *Enter moles of MnO₂:* b. **Mole Ratio Determination:** - **Reaction:** \( 3 \text{MnO}_2(s) + 4 \text{Al}(s) \rightarrow 3 \text{Mn}(s) + 2 \text{Al}_2\text{O}_3(s) \) - *Enter the mole ratio of Al to MnO₂:* c. **Reacting Moles of Al:** - *Question:* How many moles of Al are required to completely react with 0.620 mol MnO₂? - *Enter moles of Al:* d. **Mass of Al Required:** - *Question:* What is the mass of Al required? - *Enter mass of Al in grams:* e. **Formation of Iron(III) Chloride:** - **Reaction:** \( \text{Fe}(s) + \text{Cl}_2(g) \rightarrow \text{FeCl}_3(s) \) - *Question:* How many milligrams of iron(III) chloride result when 20.00 mg of iron is reacted with excess chlorine gas? - *Enter mass in mg of FeCl₃:* **3. Limiting Reagent Analysis:** a. **Amount of Acetic Acid Formed:** - *Question:* What amount of HC₂H₃O₂ can be formed from the amount of each reactant? - If all of the CH₃CHO was used up in the reaction, how many moles of HC₂H₃O₂ would be produced? - *Enter moles of HC₂
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