Here we have a charge of 2.58 x 10^-6 C moving at velocity 5.36 x 10^5 m/s through a magnetic field of strength 4.82 T and an electric field of strength 1.36 x 10^5 N/C. What is the magnitude of the total force on this charge?  4.42 N  9.47 N  11.36 N  6.31 N

An electron moves with velocity v= (7.0​i​​​−6.0​j​)×10​^4 ​​m/s in a magnetic field B = (−0.80​i​+0.60​j​)T . a. Determine the x -component of the force on the electron. b. Determine the y -component of the force on the electron. c. Determine the z -component of the force on the electron.

A magnetic field has a magnitude of 0.0014 T, and an electric field has a magnitude of 3.5 × 103 N/C. Both fields point in the same direction. A positive 1.7-μC charge moves at a speed of 2.8 x 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. Number 1+1 P90⁰ Units BA

A 60 cm long straight wire carrying a current of 4.0 A is placed in a 9.8 T magnetic field. The angle between the field and the wire is 60 degrees. What is the magnitude of the magnetic force exerted on the wire by the field? 20.4 N 28.1 N 26.7 N 15.8 N

A particle carries a charge of -3.35 x10^-8 C has a mass of 0.163 g. The particle has an initial northward velocity of 37069 m/s. What is the magnitude of the minimum magnetic field that will balance the earth's gravitational pull on the particle? Leave your answer in 1 decimal place.

Problem 5: An electron (q= -e = -1.60 × 10-19 C and me = 9.11 × 10-31 kg) in a cathode-ray tube is accelerated through a potential difference of 10 kV. Thus, the electron leaves the cathode-ray tube with a speed v = 5.93 × 107 m/sec. The electron then passes through the 2.0 cm wide region of uniform magnetic field (shown in the Figure above on the right). What field strength will deflect the electron by 10°? Answer: B = 0.0029 T. OV 10 kV 2.0 cm 10°

An electron moves through a uniform electric field E = (2.60î + 4.80ĵ) V/m and a uniform magnetic field B = 0.400 T.Determine the acceleration of the electron when it has a velocity v = 11.0î m/s.(Give each component in m/s2.) ax=           m/s2 ay=           m/s2 az=           m/s2

A charged particle moves into a region of uniform magnetic field, goes through half a circle, and then exits that region. The particle is either a proton or an electron (you must decide which). It spends 130 ns in the region. What is the magnitude of B? Give your answer in T. (mproton=1.672x1027 kg, melectron-9.1lx10-3! kg, e-1.602x10-19 C) OB

A particle with charge 8.11 x 10^-6 C moves at 4.75 x 10^6 m/s through a magnetic field of strength 4.14 T. The angle between the particle s velocity and the magnetic field direction is 55.1 degrees and the particle undergoes an acceleration of 7.7 m/s^2. What is the particle s mass?     9.2 kg   16.99 kg   3.9 kg   5.4 kg

A proton is moving in a region where the magnetic and electric fields are perpendicular to each other and produce no net force. If the electric field has a strength of 5.00 x 10^6 N/C and the magnetic field has a strength of 0.800 T, how fast was the proton moving in m/s? a. 4.00 x 10^6 m/s b.6.25x10^6 m/s  c.2.5x10^-7 m/s d.1.6x10^-7 m/s