Here are summary statistics for the weights of Pepsi in randomly selected cans: n=36, x=0.82412 lb, s = 0.00574 lb. Use a confidence level of 99% to complete parts (a) through (d) below. a. Identify the critical value tx/2 used for finding the margin of error. ¹a/2 = 2.72 (Round to two decimal places as needed.) b. Find the margin of error. E = 0.00261 lb (Round to five decimal places as needed.) c. Find the confidence interval estimate of μ. 0.82152 lb<μ< 0.82672 lb (Round to five decimal places as needed.) d. Write a brief statement that interprets the confidence interval. Choose the correct answer below. OA. One has 99% confidence that the interval from the lower bound to the upper bound contains the true value of the population mean weight of Pepsi in a can. OB. Approximately 99% of sample mean weights of Pepsi in a can will fall between the lower bound and the upper bound. OC. One has 99% confidence that the sample mean weight of Pepsi in a can is equal to the population mean weight of Pepsi in a can. OD. There is a 99% chance that the true value of the population mean weight of Pepsi in a can will fall between the lower bound and the upper bound.
Here are summary statistics for the weights of Pepsi in randomly selected cans: n=36, x=0.82412 lb, s = 0.00574 lb. Use a confidence level of 99% to complete parts (a) through (d) below. a. Identify the critical value tx/2 used for finding the margin of error. ¹a/2 = 2.72 (Round to two decimal places as needed.) b. Find the margin of error. E = 0.00261 lb (Round to five decimal places as needed.) c. Find the confidence interval estimate of μ. 0.82152 lb<μ< 0.82672 lb (Round to five decimal places as needed.) d. Write a brief statement that interprets the confidence interval. Choose the correct answer below. OA. One has 99% confidence that the interval from the lower bound to the upper bound contains the true value of the population mean weight of Pepsi in a can. OB. Approximately 99% of sample mean weights of Pepsi in a can will fall between the lower bound and the upper bound. OC. One has 99% confidence that the sample mean weight of Pepsi in a can is equal to the population mean weight of Pepsi in a can. OD. There is a 99% chance that the true value of the population mean weight of Pepsi in a can will fall between the lower bound and the upper bound.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Here are summary statistics for the weights of Pepsi in randomly selected cans: n=36, x=0.82412 lb, s = 0.00574 lb. Use a confidence level of 99% to complete parts (a) through (d) below.
a. Identify the critical value tx/2 used for finding the margin of error.
¹a/2 = 2.72
(Round to two decimal places as needed.)
b. Find the margin of error.
E = 0.00261 lb
(Round to five decimal places as needed.)
c. Find the confidence interval estimate of μ.
0.82152 lb<μ< 0.82672 lb
(Round to five decimal places as needed.)
d. Write a brief statement that interprets the confidence interval. Choose the correct answer below.
OA. One has 99% confidence that the interval from the lower bound to the upper bound contains the true value of the population mean weight of Pepsi in a can.
OB. Approximately 99% of sample mean weights of Pepsi in a can will fall between the lower bound and the upper bound.
OC. One has 99% confidence that the sample mean weight of Pepsi in a can is equal to the population mean weight of Pepsi in a can.
OD. There is a 99% chance that the true value of the population mean weight of Pepsi in a can will fall between the lower bound and the upper bound.
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