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Here are 6 celebrities with some of the highest net worths (in millions of dollars) in a recent year: Steven Spielberg (3700), Oprah Winfrey (3200) Paul McCartney (1200), J. K. Rowling (1000), David Copperfield (1000), and Jerry Seinfeld (950) . Find the range, variance, and standard deviation for the sample data. What do the results tell us about the population of all celebrities? Based on the nature of the amounts, what can be inferred about their precision? ..... The range is $million. (Round to the nearest integer as needed.) The variance is million dollars squared. (Round to the nearest integer as needed.) The standard deviation is $ million. (Round to the nearest integer as needed.) What do the results tell us about the population of all celebrities? OA. Because the statistics are calculated from the data, the measures of variation are typical for all celebrities. O B. Because the data are from celebrities with the highest net worths, the measures of variation are typical for all celebrities. O C. Because the statistics are calculated from the data, the measures of variation cannot tell us about other celebrities. O D. Because the data are from celebrities with the highest net worths, the measures of variation are not at all typical for all celebrities. Based on the nature of the amounts, what can be inferred about their precision? Because all of the amounts end with Vit appears that they are rounded to the nearest so it would make sense to round the results to the nearest

Here are 6 celebrities with some of the highest net worths (in millions of dollars) in a recent year: Steven Spielberg (3700), Oprah Winfrey (3200) Paul McCartney (1200), J. K. Rowling (1000), David Copperfield (1000), and Jerry Seinfeld (950) . Find the range, variance, and standard deviation for the sample data. What do the results tell us about the population of all celebrities? Based on the nature of the amounts, what can be inferred about their precision? ..... The range is $million. (Round to the nearest integer as needed.) The variance is million dollars squared. (Round to the nearest integer as needed.) The standard deviation is $ million. (Round to the nearest integer as needed.) What do the results tell us about the population of all celebrities? OA. Because the statistics are calculated from the data, the measures of variation are typical for all celebrities. O B. Because the data are from celebrities with the highest net worths, the measures of variation are typical for all celebrities. O C. Because the statistics are calculated from the data, the measures of variation cannot tell us about other celebrities. O D. Because the data are from celebrities with the highest net worths, the measures of variation are not at all typical for all celebrities. Based on the nature of the amounts, what can be inferred about their precision? Because all of the amounts end with Vit appears that they are rounded to the nearest so it would make sense to round the results to the nearest

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Here are 6 celebrities with some of the highest net worths (in millions of dollars) in a recent year: Steven Spielberg (3700), Oprah Winfrey (3200), Paul McCartney (1200), J. K. Rowling (1000), David Copperfield (1000), and Jerry Seinfeld (950) . Find the range, variance, and standard deviation for the sample data. What do the results tell us about the population of all celebrities? Based on the nature of the amounts, what can be inferred about their precision? The range is $ $million. (Round to the nearest integer as needed.) million dollars squared. (Round to the nearest integer as needed.) The variance is The standard deviation is $ million. (Round to the nearest integer as needed.) What do the results tell us about the population of all celebrities? O A. Because the statistics are calculated from the data, the measures of variation are typical for all celebrities. O B. Because the data are from celebrities with the highest net worths, the measures of variation are typical for all celebrities. OC. Because the statistics are calculated from the data, the measures of variation cannot tell us about other celebrities. O D. Because the data are from celebrities with the highest net worths, the measures of variation are not at all typical for all celebrities. Based on the nature of the amounts, what can be inferred about their precision? Because all of the amounts end with it appears that they are rounded to the nearest so it would make sense to round the results to the nearest
Transcribed Image Text:Here are 6 celebrities with some of the highest net worths (in millions of dollars) in a recent year: Steven Spielberg (3700), Oprah Winfrey (3200), Paul McCartney (1200), J. K. Rowling (1000), David Copperfield (1000), and Jerry Seinfeld (950) . Find the range, variance, and standard deviation for the sample data. What do the results tell us about the population of all celebrities? Based on the nature of the amounts, what can be inferred about their precision? The range is $ $million. (Round to the nearest integer as needed.) million dollars squared. (Round to the nearest integer as needed.) The variance is The standard deviation is $ million. (Round to the nearest integer as needed.) What do the results tell us about the population of all celebrities? O A. Because the statistics are calculated from the data, the measures of variation are typical for all celebrities. O B. Because the data are from celebrities with the highest net worths, the measures of variation are typical for all celebrities. OC. Because the statistics are calculated from the data, the measures of variation cannot tell us about other celebrities. O D. Because the data are from celebrities with the highest net worths, the measures of variation are not at all typical for all celebrities. Based on the nature of the amounts, what can be inferred about their precision? Because all of the amounts end with it appears that they are rounded to the nearest so it would make sense to round the results to the nearest
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