Henry performed a two-tailed test for an experiment in which N = 24. He could not find his table of t critical values, but he remembered the tcv at df= 13. He decided to compare his tobt with this tcv. Is he more likely to make a Type I or a Type II error in this situation?
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Henry performed a two-tailed test for an experiment in which N = 24. He could not find his table of t critical values, but he remembered the tcv at df= 13. He decided to compare his tobt with this tcv. Is he more likely to make a Type I or a Type II error in this situation?
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- An experiment was conducted to test the effect of a new cholesterol medicine. Fifteen people were treated with medicine X and 15 with medicine Y for a month, then the subjects' cholesterol level was measured. A significance test was conducted at the a = 0.01 level for the difference in the means of the cholesterol levels between medicine X and medicine Y. The test resulted in t = 2.73 and p = 0.003. If the alternative hypothesis in question was Ha: px - μy ‡ 0, where µx equals the mean cholesterol level for subjects taking medicine X and μy equals the mean cholesterol level for subjects taking medicine Y, what conclusion can be drawn? O There is not a significant difference in mean cholesterol level when using medicine X and medicine Y. O There is sufficient evidence that there is a difference in mean cholesterol level when using medicine X and medicine Y. O There is sufficient evidence that medicine X lowers cholesterol levels more than medicine Y. O The proportion of subjects who…Also, using α = .05, run a two-tail t-test for one sample to test Ho: µ=283 for the 2009 scores. Report the t-obt, df, and p-values. Would you reject the null hypothesis that the 2009 scores come from a population with average 283? If this is the case, does it come from a population from larger or smaller average?An experiment was conducted to test the effect of a new stain remover. Twenty stains were treated with stain remover A and stain remover B for a week, then the number of stains removed was measured. A significance test was conducted at the a = 0.10 level for the difference in the means of the number of stains removed between stain remover A and stain remover B. The test resulted in t = 1.37 and p = 0.17. If the alternative hypothesis in question is Ha: HA - HB #0, where μA equals the mean number of stains removed with stain remover A and μg equals the mean number of stains removed with stain remover B, what conclusion can be drawn? O There is a significant difference in the mean effectiveness of two stain removers. O There is sufficient evidence that stain remover A works better than stain remover B. O The proportion of stains that stain remover A removed is greater than the proportion of stains removed by stain remover B. O There is insufficient evidence that the proportion of stains…
- Arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The 142 pairs of measurements yield x=32.14cm, y=163.36cm, r=.084, P value=.32 and y=160+.111x. Find the best predicted value of y (height) given an adult female with an arm circumference of 40cm. Let the predictor variable x be arm circumference and the response variable y be height. Use a .05 significance level.A hairdresser wanted to see if her clients bought more products at the end of their appointment if they were given lots of compliments. She decided to test this theory using an experiment. She randomly assigned 24 clients to receive either zero compliments, 5 compliments, or 10 compliments during their appointment. She recorded how many products they purchased after their appointment as her DV. She firstly hypothesised that no-compliment clients (M = 0.38) would purchase fewer products than clients who received 5 compliments (M = 1.50). She secondly hypothesised that 5-compliment clients would purchase fewer products than 10-compliment clients (M = 3.63). Thus, she conducted two comparisons. The initial ANOVA was significant. Using an alpha of .05, results for the follow-up tests confirmed her first hypothesis, with an obtained t value of 2.60, but did not confirm her second hypothesis, with an obtained t value of 1.20. She later realised that she did not use a Bonferroni-corrected…A researcher would like to examine how the chemical tryptophan, contained in foods such as turkey, can affect mental alertness. A sample of n = 9 college students is obtained, and each student’s performance on a familiar video game is measured before and after eating a traditional Thanksgiving dinner including roast turkey. The average score dropped by MD = 14 points after the meal with SS = 1152 for the difference scores. What type of t-test would you have to conduct in this scenario?Are the data sufficient to conclude that the treatment has a significant effect? Use a two-tailed test with α = .05. State the hypothesis, find the critical region, calculate your test statistic, and evaluate your hypothesis then calculate the Cohen’s d measure for this scenario. State whether this is a weak, moderate, or strong effect.
- According to the American Pet Products Manufacturers Association, cat owners spend an average of $179 annually in routine veterinary visits. A random sample of local cat owners revealed that ten randomly selected owners spent an average of $205 with s = $26. Is there a significant statistical difference at α = 0.01?The test statics isI AM RESUBMITTING THIS QUESTION FOR MORE HELP. I AM AT THE P-VALUE, SECOND NUMBER 2 QUESTION. The recidivism rate for convicted sex offenders is 16%. A warden suspects that this percent is higher if the sex offender is also a drug addict. Of the 318 convicted sex offenders who were also drug addicts, 54 of them became repeat offenders. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer ≠ = > < (please enter a decimal) H1: ? μ p Select an answer ≠ < = > (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is…The athletic director at a large university compared the proportions of freshmen (1st year students) and seniors (4th year students) who exercise regularly. She analyzed the data and found the Z-statistic for the difference between the population proportions to be 2.43 with a P-value of 0.015. The level of significance was set at 0.05. State the conclusion she can draw about the difference between the two population proportions.
- I missed a few of these on the last question if you could kindly check over them and help wherever they are incorrect.. 8% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 345 people from the inner city surveyed, 24 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.10? For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly smaller than 8% at αα = 0.10, so there is sufficient evidence to conclude that the population proportion…he personality trait of "Conscientiousness" (someone who is organized, responsible, and can control their impulses) has μ = 120 and σ =9. Test whether ARC students (n = 9, M = 126) differ on Conscientiousness. α = .05. What is the correct result based on the data?To examine the relationship between alcohol consumption and birth weight, a researcher selects a sample of n = 20 pregnant rats and mixes alcohol with their food for 2 weeks before the pups are born. One newborn pup is randomly selected from each subject’s litter and the average with weight for the n = 20 pups is recorded. It is known that the average birth weight for regular rats (without exposure to alcohol) is μ = 5.6 grams. What type of test would you use to test the hypothesis that alcohol consumption during pregnancy reduces birth weights? Would you use a one-tailed or two-tailed test? What would be an appropriate measure of effect size to report?
