Hello,     Please help with the following question:   A panda wants to swing on a vine like tarzan, creating a simple panda-lum. Unfortunately, the vine is too weak to handle the tension created by the panda.   The panda starts at a point with the vine outstretched horizontally to its fulllength l and that makes a 90 degree angle with the vertical. If the panda has a mass m and the max tension in the rope is T , show that the speed of tha panda when the vine breaks is: v = Square Root of 2lT/3m

A gymnast is swinging on a high bar. The distance between his waist and the bar is 1.28 m, as the drawing shows. At the top of the swing his speed is momentarily zero. Ignoring friction and treating the gymnast as if all of his mass is located at his waist, find his speed at the bottom of the swing.

(a) A stuntman with a mass of 81.5 kg swings across a pool of water from a rope that is 11.0 m. At the bottom of the swing the stuntman's speed is 7.90 m/s. The rope's breaking strength is 1,000 N. Will the stuntman make it across the pool without falling in? O Yes O No (b) What If? What is the maximum speed (in m/s) that the stuntman can have at the bottom of the swing on this vine to safely swing across the river? m/s

A 5.60-kg block is set into motion up an inclined plane with an initial speed of v¡ = 7.60 m/s (see figure below). %3D The block comes to rest after traveling d = 3.00 m along the plane, which is inclined at an angle of 0 = 30.0° to the %3D horizontal. (a) For this motion, determine the change in the block's kinetic energy. We know an initial speed and a final speed. Are the other pieces of information relevant to this question? J (b) For this motion, determine the change in potential energy of the block-Earth system. 82.3 J (c) Determine the friction force exerted on the block (assumed to be constant). You appear to have correctly calculated the force using your incorrect results from parts (a) and (b). N (d) What is the coefficient of kinetic friction? You appear to have calculated the coefficient correctly using your incorrect result from part (c).

A box of mass 4.0 kg hangs by a cable from the ceiling of an elevator. The elevator is moving up at a steady speed of 5.0 m/s for 8.0 m. Use g = 10 m/s2. Consider the system is the box and the Earth. When apply the following energy principle, considering the system is box+earth, which of the energy term is positive? Select all apply. ΔK + ΔUg + ΔUsp + ΔEth + ΔEch = Wext Answer choice     ΔK     ΔUg      ΔUsp     ΔEth      ΔEch     Wext

A 1700 kg car starts up a 130 m long hill at a speed of 20.0 m/s. If the propulsive force (up the slope) is 15.0 kN, while the resistive force (due to friction/AR) is 8.79 kN, then determine the car's kinetic energy when it reaches a vertical height of 48.1 m at the top of the hill. can you please write it down instead so I can follow it better

A girl is awinging on a swing At the highest point, she is 3.8 meters from the ground. At the lowest point, the is 0.5 meters from the ground. Neglecting friction and air resistance, what will be her maximum speed? 10.4 m 3.8 m 0.5 m