Hello, can you please help me solve this question ? This is a confidence interval level question : In a poll of 1000 adults, 341 said they were comfortable with technology. Construct a 95% confidence interval estimate of the proportion of adults who are comfortable with technology. I have attempted to solve this twice but I am doing something wrong.

Confidence interval:

The (1-α) % confidence interval for proportion p is given by,

Computing the 99% confidence interval for population proportion:

It was found that, 341 out of the 1,000 adults said that they were comfortable.

That is, n=1,000 and the sample proportion, p-hat = 0.341 (=341/1,000). The confidence level is 95%. Therefore, the significance level, α = 0.05 and the z value corresponding to α/2 is 1.96.  The 95% confidence interval for population proportion is given by: