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- Complete the following missing code: void insert_after(int key, int value) { node *myNode =new node; myNode=head; int flag = 0; while(myNode!=NULL) { } if(flag==0) cout<bool DelOddCopEven(Node* headPtr);#ifndef LLCP_INT_H#define LLCP_INT_H #include <iostream> struct Node{ int data; Node *link;}; bool DelOddCopEven(Node* headPtr);int FindListLength(Node* headPtr);bool IsSortedUp(Node* headPtr);void InsertAsHead(Node*& headPtr, int value);void InsertAsTail(Node*& headPtr, int value);void InsertSortedUp(Node*& headPtr, int value);bool DelFirstTargetNode(Node*& headPtr, int target);bool DelNodeBefore1stMatch(Node*& headPtr, int target);void ShowAll(std::ostream& outs, Node* headPtr);void FindMinMax(Node* headPtr, int& minValue, int& maxValue);double FindAverage(Node* headPtr);void ListClear(Node*& headPtr, int noMsg = 0); // prototype of DelOddCopEven of Assignment 5 Part 1 #endif // definition of DelOddCopEven of Assignment 5 Part 1//Algorithm should: /*NOT destroy any of the originally even-valued node. This means that the originally even-valued nodes should be retained as part of the resulting list. Destroy…
- remove(x) This operation removes element from the set.If element does not exist, it raises a KeyError.The .remove(x) operation returns None. Example >>> s = set([1, 2, 3, 4, 5, 6, 7, 8, 9]) >>> s.remove(5) >>> print s set([1, 2, 3, 4, 6, 7, 8, 9]) >>> print s.remove(4) None >>> print s set([1, 2, 3, 6, 7, 8, 9]) >>> s.remove(0) KeyError: 0 .discard(x) This operation also removes element from the set.If element does not exist, it does not raise a KeyError.The .discard(x) operation returns None. Example >>> s = set([1, 2, 3, 4, 5, 6, 7, 8, 9]) >>> s.discard(5) >>> print s set([1, 2, 3, 4, 6, 7, 8, 9]) >>> print s.discard(4) None >>> print s set([1, 2, 3, 6, 7, 8, 9]) >>> s.discard(0) >>> print s set([1, 2, 3, 6, 7, 8, 9]) .pop() This operation removes and return an arbitrary element from the set.If there are no elements to remove, it raises a KeyError. Example…Part 2: Create the following struct: struct nodeType { Point value; nodeType * Link; };flip_matrix(mat:list)->list You will be given a single parameter a 2D list (A list with lists within it) this will look like a 2D matrix when printed out, see examples below. Your job is to flip the matrix on its horizontal axis. In other words, flip the matrix horizontally so that the bottom is at top and the top is at the bottom. Return the flipped matrix. To print the matrix to the console: print('\n'.join([''.join(['{:4}'.format(item) for item in row]) for row in mat])) Example: Matrix: W R I T X H D R L G L K F M V G I S T C W N M N F Expected: W N M N F G I S T C L K F M V H D R L G W R I T X Matrix: L C S P Expected: S P L C Matrix: A D J A Q H J C I Expected: J C I A Q H A D J
- #ifndef LLCP_INT_H#define LLCP_INT_H #include <iostream> struct Node{ int data; Node *link;};void DelOddCopEven(Node*& headPtr);int FindListLength(Node* headPtr);bool IsSortedUp(Node* headPtr);void InsertAsHead(Node*& headPtr, int value);void InsertAsTail(Node*& headPtr, int value);void InsertSortedUp(Node*& headPtr, int value);bool DelFirstTargetNode(Node*& headPtr, int target);bool DelNodeBefore1stMatch(Node*& headPtr, int target);void ShowAll(std::ostream& outs, Node* headPtr);void FindMinMax(Node* headPtr, int& minValue, int& maxValue);double FindAverage(Node* headPtr);void ListClear(Node*& headPtr, int noMsg = 0); // prototype of DelOddCopEven of Assignment 5 Part 1 #endiftypedef struct node{int data;struct node *left,*right;}BST;The node structure of BST is shown above. Please design an efficient algorithm to return the maximum keyword value in BST. Completion function: int findmax (BST *T)Write a c++ code of link list which is used to take your data like name, mob, age , marks. After that you will display the data in Disp() function. Your code will be able to take 5 students data and also check which student marks is greater than from other. At the end you will delete any node from link list Please should create grading_fun(); Bonus > 80 A 70 B 60 C 50 D
- struct nodeType { int infoData; nodeType * next; }; nodeType *first; … and containing the values(see image) Using a loop to reach the end of the list, write a code segment that deletes all the nodes in the list. Ensure the code performs all memory ‘cleanup’ functions.What happens when a programmer attempts to access a node's data fields when the node variable refers to None? How do you guard against it? *PYTHONCreate a method that accepts a pointer to a Node structure as an argument and returns a full copy of the data structure put in. There are two pointers to other Nodes in the Node data structure.