he vector x is in a subspace H with a basis B = {b₁,b₂}. Find the B-coordinate vecto b₁ X]B = 5 -7 b₂ = 1 3 5 1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Problem Statement:**

The vector **x** is in a subspace **H** with a basis **B** = {**b₁**, **b₂**}. Find the B-coordinate vector of **x**.

**Given:**

\[ 
\mathbf{b}_1 = 
\begin{bmatrix}
5 \\
-7 
\end{bmatrix}, \quad
\mathbf{b}_2 = 
\begin{bmatrix}
-1 \\
3 
\end{bmatrix}, \quad
\mathbf{x} = 
\begin{bmatrix}
5 \\
1 
\end{bmatrix} 
\]

**Required:**

\[ 
[\mathbf{x}]_B = \, \_ 
\]

---

**Explanation:**

To find the B-coordinate vector [**x**]_B, we need to express vector **x** as a linear combination of the basis vectors **b₁** and **b₂**. That is, we need to find scalars \(c_1\) and \(c_2\) such that:

\[ 
\mathbf{x} = c_1 \mathbf{b}_1 + c_2 \mathbf{b}_2 
\]

Substituting the given vectors, we have:

\[ 
\begin{bmatrix}
5 \\
1 
\end{bmatrix} = c_1 
\begin{bmatrix}
5 \\
-7 
\end{bmatrix} + c_2 
\begin{bmatrix}
-1 \\
3 
\end{bmatrix} 
\]

This equation represents a system of linear equations:

\[ 
5c_1 - c_2 = 5 
\]
\[ 
-7c_1 + 3c_2 = 1 
\]

Solving this system using methods such as substitution, elimination, or matrix operations will give the values of \(c_1\) and \(c_2\). These values constitute the components of the B-coordinate vector [**x**]_B.

---

**Graphical/Diagram Explanation:**

Given the problem statement and equations, this exercise falls under the topic of vector spaces and coordinate systems in Linear Algebra. The solution requires solving a system of linear equations which would typically involve using matrix techniques such as Gaussian elimination.
Transcribed Image Text:**Problem Statement:** The vector **x** is in a subspace **H** with a basis **B** = {**b₁**, **b₂**}. Find the B-coordinate vector of **x**. **Given:** \[ \mathbf{b}_1 = \begin{bmatrix} 5 \\ -7 \end{bmatrix}, \quad \mathbf{b}_2 = \begin{bmatrix} -1 \\ 3 \end{bmatrix}, \quad \mathbf{x} = \begin{bmatrix} 5 \\ 1 \end{bmatrix} \] **Required:** \[ [\mathbf{x}]_B = \, \_ \] --- **Explanation:** To find the B-coordinate vector [**x**]_B, we need to express vector **x** as a linear combination of the basis vectors **b₁** and **b₂**. That is, we need to find scalars \(c_1\) and \(c_2\) such that: \[ \mathbf{x} = c_1 \mathbf{b}_1 + c_2 \mathbf{b}_2 \] Substituting the given vectors, we have: \[ \begin{bmatrix} 5 \\ 1 \end{bmatrix} = c_1 \begin{bmatrix} 5 \\ -7 \end{bmatrix} + c_2 \begin{bmatrix} -1 \\ 3 \end{bmatrix} \] This equation represents a system of linear equations: \[ 5c_1 - c_2 = 5 \] \[ -7c_1 + 3c_2 = 1 \] Solving this system using methods such as substitution, elimination, or matrix operations will give the values of \(c_1\) and \(c_2\). These values constitute the components of the B-coordinate vector [**x**]_B. --- **Graphical/Diagram Explanation:** Given the problem statement and equations, this exercise falls under the topic of vector spaces and coordinate systems in Linear Algebra. The solution requires solving a system of linear equations which would typically involve using matrix techniques such as Gaussian elimination.
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