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he truth table of X-OR gate is given as r input 'Xo and X1 and select input 'S' the pression of the output 'Y' of the ultiplexer is given as Xo + SX, ep 2 -w in order to make X-OR gate using 2:1 JX, erefore the X-OR gate using 2:1 MUX is plemented as

he truth table of X-OR gate is given as r input 'Xo and X1 and select input 'S' the pression of the output 'Y' of the ultiplexer is given as Xo + SX, ep 2 -w in order to make X-OR gate using 2:1 JX, erefore the X-OR gate using 2:1 MUX is plemented as

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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1AcLurumng to quesuOn. The truth table of X-OR gate is given as B. For input 'Xo and X1 and select input 'S' the expression of the output 'Y' of the multiplexer is given as F = SXo + SX, Step 2 Now in order to make X-OR gate using 2:1 MUX, S = A Xo = B X, = B Therefore the X-OR gate using 2:1 MUX is implemented as 2:1 MUX 2:1 MUX The output of MUX 1 gives B And the output of MUX 2 gives F = AB+ AB
Transcribed Image Text:1AcLurumng to quesuOn. The truth table of X-OR gate is given as B. For input 'Xo and X1 and select input 'S' the expression of the output 'Y' of the multiplexer is given as F = SXo + SX, Step 2 Now in order to make X-OR gate using 2:1 MUX, S = A Xo = B X, = B Therefore the X-OR gate using 2:1 MUX is implemented as 2:1 MUX 2:1 MUX The output of MUX 1 gives B And the output of MUX 2 gives F = AB+ AB
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