Answered: he mean family income for a random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean family income for a random sample of 700 suburban households in Guinesstowne shows that a 90 percent confidence interval is ($47,250, $62,100). Herman is conducting a test of the null hypothesis H₀: µ = 45,000 against the alternative hypothesis H_a: µ ≠ 45,000 at the α = 0.10 level of significance. Does Herman have enough information to conduct a test of the null hypothesis against the alternative?

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Yes, because $45,000 is not contained in the 90% confidence interval, the null hypothesis would not be rejected, and it could be concluded that the mean family income is not significantly different from $45,000 at the α = 0.10 level

Yes, because $45,000 is not contained in the 90% confidence interval, the null hypothesis would be rejected in favor of the alternative, and it could be concluded that the mean family income is significantly different from $45,000 at the α = 0.10 level

No, because the value of σ is not known

No, because it is not known whether the data are Normally distributed

No, because the entire data set is needed to do this test

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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