he freezing point of benzene, C6H6, is 5.500 °C at 1 atmosphere. Kbenzene) = -5.12 °C/m a laboratory experiment, students synthesized a new compound and found that when 11.50 grams of the compound were dissolved in 250.5 grams of benzene, the solution began to freeze at 4.685 °C. The compou o be nonvolatile and a non-electrolyte. /hat is the molecular weight they determined for this compound ? g/mol

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter6: Solutions And Colloids
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Problem 6.63P
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The freezing point of benzene, C6H6, is 5.500 °C at 1 atmosphere. Kf(benzene) = -5.12 °C/m
In a laboratory experiment, students synthesized a new compound and found that when 11.50 grams of the compound were dissolved in 250.5 grams of benzene, the solution began to freeze at 4.685 °C. The compound was also found
to be nonvolatile and a non-electrolyte.
What is the molecular weight they determined for this compound ?
g/mol
Transcribed Image Text:The freezing point of benzene, C6H6, is 5.500 °C at 1 atmosphere. Kf(benzene) = -5.12 °C/m In a laboratory experiment, students synthesized a new compound and found that when 11.50 grams of the compound were dissolved in 250.5 grams of benzene, the solution began to freeze at 4.685 °C. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight they determined for this compound ? g/mol
Boiling Point Elevation/Freezing Point Depression
AT= m K
where, for freezing point depression:
AT= T(pure solvent) - T(solution)
and for boiling point elevation:
AT= T(solution) - T(pure solvent)
m = (# moles solute / Kg solvent)
Kp = boiling point elevation constant.
Kf = freezing point depression constant.
K, and Kf depend only on the SOLVENT. Below are some common values. Use these values for the calculations that follow.
Solvent
Formula
Kh(^C / m) KfºC/m)
Water
H20
0.512
1.86
Ethanol
CH3CH2OH
1.22
1.99
Chloroform CHC13
3.67
Benzene
CGH6
2.53
5.12
Diethyl ether CH3CH2OCH2CH3
2.02
Transcribed Image Text:Boiling Point Elevation/Freezing Point Depression AT= m K where, for freezing point depression: AT= T(pure solvent) - T(solution) and for boiling point elevation: AT= T(solution) - T(pure solvent) m = (# moles solute / Kg solvent) Kp = boiling point elevation constant. Kf = freezing point depression constant. K, and Kf depend only on the SOLVENT. Below are some common values. Use these values for the calculations that follow. Solvent Formula Kh(^C / m) KfºC/m) Water H20 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHC13 3.67 Benzene CGH6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02
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