Find an equation of the tangent line to the given curve at the specified point. 1 + x 6 + ex' (0, -1/-) y = y =

I need the equation of the tangent line to the curve at (1,3)

Find the equation of the tangent line at the given point on the curve. x² + y² = xe5y-y²5x12. (2,1) y=0 ***