This is homework Hardware & Architecture Homework #2-100 PtsAnswer the following questions, showing your work where appropriate:provided represents an unsigned value.1. (36 Pts 1 Pt Each) Convert the following values to the other bases. Assume each valueFor binary values, include leading zeros, as needed, to the nearest group of 4 bits(Example: 123(Hex)-0001 0010 0011(Binary)...note the leading zeros in red.)Binary01011101HexadecimalDecimal2.5B65071010011129D8,154011011001677420001010010111111109E9,0761110000000100011F8A41,40811111001001010003CB22,090(4 Pts 2 Pts Each) If a computer has 12-bit addresses,-a. How many addresses are possible?b. Assuming that addressing begins at zero, what is the decimal value of the highest address?

1.Example: How to get the Hexadecimal and decimal using BinaryBinary: 01011101Hexadecimal (group it…

Answered: Hardware & Architecture Homework #2-100…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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VI. Floating point representation Consider a 12-bit variant of the IEEE floating point format as follows: • Sign bit 5-bit exponent with a bias of 15. • 6-bit significand All of the rules for IEEE 754 Standard apply. Fill in the numeric value represented by the following bit patterns. You must write your number in decimal form (e.g. 0.0146485375, -0.0146485375). Bit Pattern 010011101110 111011101011 100101001111 001010111010 Numerical Value
Assignment for Computer Architecture! this is about hamming codes write the code IN MIPS ASSEMBLY LANGUAGE calculating hamming codes; The key to the Hamming Code is the use of extra parity bits to allow the identification of a single error. Create the code word as follows: Mark all bit positions that are powers of two as parity bits. (positions 1, 2, 4, 8, 16, 32, 64, etc.) All other bit positions are for the data to be encoded. (positions 3, 5, 6, 7, 9, 10, 11, 12, 13, 14, 15, 17, etc.) Each parity bit calculates the parity for some of the bits in the code word. The position of the parity bit determines the sequence of bits that it alternately checks and skips.Position 1: check 1 bit, skip 1 bit, check 1 bit, skip 1 bit, etc. (1,3,5,7,9,11,13,15,...)Position 2: check 2 bits, skip 2 bits, check 2 bits, skip 2 bits, etc. (2,3,6,7,10,11,14,15,...)Position 4: check 4 bits, skip 4 bits, check 4 bits, skip 4 bits, etc. (4,5,6,7,12,13,14,15,20,21,22,23,...)Position 8: check 8 bits,…
Floating point calculation: a Show the IEEE 754 representation for the decimal value -0.375 in single precision b. Find the decimal representation for the following single precision floating point number 1011,1111,0111,0000,0000,0000,0000,0000 c. Perform the addition and multiplication of the two floating point numbers in (a) and (b) in binary scientific notation, and represent the sum and product in single precision.
What is al and the carry flag after the following code executes? mov al, 11110100b sar al, 3 Fill in the blank for al with an 8 bit binary number including leading zeros if necessary. For example: 00101000 Note: no spaces and no 'b. Fill in the blank for the carry flag (cf) with a 0 or 1 with no 'b'. al = b CF =
Questi on 1: This problem covers 4-bit binary multiplication. Fill in the table for the Product, Multiplier and Multiplicand for each step. You need to provide the DESCRIPTION of the step being performed (shift left, shift right, add, no add). The value of M (Multiplicand) is 1100, Q (Multiplier) is initially 0111. Product Multiplicand Multiplier Description Step 0000 0000 0000 1100 0111 Initial Values Step 0 Step 1 Step 2 Step 3 Step 4 Step 5 Step 6 Step 7 Step 8. Step 9 Step 10 Step 11 Step 12 Step 13 Step 14 Step 15
True/False In Floating Point Addition, the exponents of the two numbers being added need to be made equal before the mantissa fields can be added, as this ensures that the bit positional values are now aligned
Assignment 1 Nile Universi 6. The following decimal numbers are shown in sign-magnitude form: +9,286 and +801. Convert them to signed-10's-complement form and perform the following operations (note that the sum is +10,627 and requires five digits and a sign). a) (+9,286)+ (+801) b) (+9,286)+ (-801) c) (-9,286) + (+801) d) (-9,286) + (-801)
Q2. (a) Convert the following numbers from one base to another. . (111.1011011), = (?)hs (2) ii. (512.5625)10 = (?)h (2) i. (153.47), = (?)1e (2)
1. A CRC code uses the following generator: G = 0x225. Codewords have 8 data bits. (a) Write the binary representation of G. (b) Write the polynomial representation of G. (c) How many CRC bits are there in a codeword? (d) Calculate the corresponding codeword for the following information bits: 0010 0011. Please provide clear explanation
Question 11 Not yet answered P Flag question A computer system uses 8 bits to represent floating-point values. The 8 bits are organised as follows: The first bit is a sign bit (0 for positive, 1 for negative). The middle 3 bits are the exponent, which uses bias of 3. The last 4 bits are the significand, which is normalised in the same way as the significand is normalised in IEEE-754 formats. The format does not reserve any special values. The following arithmetic operation is performed on this system: 00011000 x 11000110 The result is then stored in the same 8-bit floating-point format. What is the relative error of the stored result comapred to the value of the result of the arithmetic operation? Answer s are rounded to 5 decimal places. O a. None of the other answers. O b. 0.03030% O c. 0.03125% O d. 0.97865% O e. 0%
1. In a binary coded decimal (BCD) system, 4 bits are used to represent a decimal digit from 0 to 9. For example, 3710 is written as 00110111BCD. (a) Write 28910 in BCD (b) Convert 100101010001BCD to decimal (c) Convert 01101001BCD to binary (d) Explain why BCD might be a useful way to represent numbers
*explain plz* You need to explain for each question why you chose True/False as your answer. [6]Assume data toe Int is 32 bits lone and uses a two's- complement representation for signed values The variables are declared and initialized as tollows: int x= too: / Arbitrary value */ int V = barl.* Arbitrary value */ unsigned ux = x: unsigned u = y: The following C expression is true (evaluates to 1) for all values of x and y: x+y == uy+ux. Hint: Think about what happens at bit-level T/F [7] Assume variables ×, f, and d are of type int, float, and double, respectively. Their values are arbitrary except that neither f nor d equals to, -o, or NaN. The following C expression is false (evaluates to 1) for all values off: f== (float)(double) f. T/F [9] When the sign bit is 1, but the other fields are all zeros, we get the value -0.0. T/F

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