H2O is the reducing agent, and O in H2O has an oxidation number of 2-.

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Chapter1: Chemical Foundations
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Use the following redox equation to select the true statement. 

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A. H2O is the oxidizing agent, and H in H2O has an oxidation number of 1+.
B. H2O is the reducing agent, and O in H2O has an oxidation number of 2-.
C. N in N2 has an oxidation number of 0, and it is the reducing agent.
D. N in N2 has an oxidation number of 2+, and it is the oxidizing agent.
Use the following redox equation to select the true statement.
2N:(g) + 6H;0(1)→ 4NH:(g) + 302(g)
H20 is the oxidizing agent, and H in H20 has an oxidation number of 1+.
O H20 is the reducing agent, and O in H20 has an oxidation number of 2-.
N in N2 has an oxidation number of 0, and it is the reducing agent.
N in N2 has an oxidation number of 2+, and it is the oxidizing agent.
Transcribed Image Text:Use the following redox equation to select the true statement. 2N:(g) + 6H;0(1)→ 4NH:(g) + 302(g) H20 is the oxidizing agent, and H in H20 has an oxidation number of 1+. O H20 is the reducing agent, and O in H20 has an oxidation number of 2-. N in N2 has an oxidation number of 0, and it is the reducing agent. N in N2 has an oxidation number of 2+, and it is the oxidizing agent.
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