Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 81IL
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Use the following redox equation to select the true statement.
(picture attached)
A. H2O is the oxidizing agent, and H in H2O has an oxidation number of 1+.
B. H2O is the reducing agent, and O in H2O has an oxidation number of 2-.
C. N in N2 has an oxidation number of 0, and it is the reducing agent.
D. N in N2 has an oxidation number of 2+, and it is the oxidizing agent.
![Use the following redox equation to select the true statement.
2N:(g) + 6H;0(1)→ 4NH:(g) + 302(g)
H20 is the oxidizing agent, and H in H20 has an oxidation number of 1+.
O H20 is the reducing agent, and O in H20 has an oxidation number of 2-.
N in N2 has an oxidation number of 0, and it is the reducing agent.
N in N2 has an oxidation number of 2+, and it is the oxidizing agent.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1290e653-b206-4ea8-8527-a4dd2bf5953e%2F259672d0-3b2c-40fa-ae50-76cd3c9d4d24%2Fodi1i4g_processed.png&w=3840&q=75)
Transcribed Image Text:Use the following redox equation to select the true statement.
2N:(g) + 6H;0(1)→ 4NH:(g) + 302(g)
H20 is the oxidizing agent, and H in H20 has an oxidation number of 1+.
O H20 is the reducing agent, and O in H20 has an oxidation number of 2-.
N in N2 has an oxidation number of 0, and it is the reducing agent.
N in N2 has an oxidation number of 2+, and it is the oxidizing agent.
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