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h (8) for h(8) = sec(√6). Oh (8) = 28 Oh (e) = sec(√) tan (√) sec(√) tan(√) On Oh (0) = sec² (2√6) Oh (8) = Oh (8) = tan² (√6) 28 sec² (√6) 28

h (8) for h(8) = sec(√6). Oh (8) = 28 Oh (e) = sec(√) tan (√) sec(√) tan(√) On Oh (0) = sec² (2√6) Oh (8) = Oh (8) = tan² (√6) 28 sec² (√6) 28

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(b) h (e) for h(e) = sec(√6). Oh (8) = 2√6 Oh'(0) = sec(√) tan (√) sec(√) tan(a) Oh'(0) = sec² (2√6) tan² (√) 2√8 (0).40 (@).40 sec² (√) 2 6
Transcribed Image Text:(b) h (e) for h(e) = sec(√6). Oh (8) = 2√6 Oh'(0) = sec(√) tan (√) sec(√) tan(a) Oh'(0) = sec² (2√6) tan² (√) 2√8 (0).40 (@).40 sec² (√) 2 6
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