H = (123 11 1 2 4 6 ) ; J = (2 4 2 1 6 1 29 2) ; K = (1 2 3 0 1 1 2 5 0 ) %3D

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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5.C) calculate the determinant
5c.
H = (1 2 3 1 1 1 2 4 6 ) ;
J = (2 4 2 1 6 1 2 9 2 ) ;
K = (1 2 3 0 1 1 2 5 0 )
Hitunglah determinannya
Transcribed Image Text:5c. H = (1 2 3 1 1 1 2 4 6 ) ; J = (2 4 2 1 6 1 2 9 2 ) ; K = (1 2 3 0 1 1 2 5 0 ) Hitunglah determinannya
Expert Solution
Step 1

The objective is to find the determinant for H=1 2 3 1 1 1 2 4 6J=2 4 2 1 6 1 2 9 2 and K=1 2 3 0 1 1 2 5 0.

The determinant of H=1 2 3 1 1 1 2 4 6 is,

H=123111246=1(6-4)-2(6-2)+3(4-2)=2-4+6=4

The determinant for J=2 4 2 1 6 1 2 9 2 is,

J=242161292=2(12-9)-4(2-2)+2(9-12)=6-6=0

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