106 -10 -9 -8 -7 -6 10 8 7 6 S 4 3 2 - ° -5 -4 -3 -2 -1 -1 -2 -3 -4 -5 9 -6 0 5- -7 -8 -9 10 10. 1 2 3 4 10 5 6 7 8 6. 9 110 Graph the system of inequalities on the coordinate plane. Label a solution point S. y ≤ 3x-1 ly > 10x+5
we graph the inequalities on the coordinate plane. We start by graphing the lines y=3x−1y=3x-1 and y=10x+5y=10x+5. Since the inequalities include '≤' and '>', we draw a solid line for y=3x−1y=3x-1 and a dashed line for y=10x+5y=10x+5.
Then, we shade the region below the line y=3x−1y=3x-1 and above the line y=10x+5y=10x+5. The intersection of these two shaded regions represents the solution to the system of inequalities.
identify a point in the intersection of the shaded regions. This point is a solution to the system of inequalities. We label this point as S.
Please note that the exact coordinates of point S will depend on the specific graph and the intersection of the shaded regions. Therefore, without a specific graph, we cannot provide the exact coordinates of point.
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110](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff20a3553-bb72-4716-af09-999137505d18%2F5e04d826-7f05-40bf-83f3-cc5f6971833d%2Fcc2qdn_processed.jpeg&w=3840&q=75)
![Graph the system of inequalities on the coordinate plane. Label a solution point S.
y ≤ 3x-1
ly > 10x+5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff20a3553-bb72-4716-af09-999137505d18%2F5e04d826-7f05-40bf-83f3-cc5f6971833d%2F67oj0le_processed.jpeg&w=3840&q=75)
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