Graph the feasible region for the follow system of inequalities by drawing a polygon around the feasible x + y <8 -x+y > 3 > 1 region. Click to set the corner points. + 8 + 7 6 5 4 3 2 1 -1+ 1 2 3 5 6 X 8

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### Graphing Linear Inequalities: Feasible Region

To understand how to graph the feasible region for a system of linear inequalities, we will analyze an example system and illustrate it on a Cartesian plane. Below is a system of inequalities and an empty graph where we can plot these inequalities to visualize the feasible region.

#### System of Inequalities

\[ 
\begin{cases}
   x + y \leq 8 \\
   -x + y \geq 3 \\
   x \geq 1 
\end{cases}
\]

### Steps for Graphing

1. **Graph each inequality separately**:
   - **Equation 1: \(x + y \leq 8\)** 
     - Convert the inequality into an equation: \(x + y = 8\).
     - Find the intercepts: 
        - When \(x = 0\), \(y = 8\) (point \((0,8)\)).
        - When \(y = 0\), \(x = 8\) (point \((8,0)\)).
     - Draw the line through these points.
     - Shade the area below this line (since \(y\) is less than or equal to the expression \(8 - x\)).
 
   - **Equation 2: \(-x + y \geq 3\)**
     - Convert the inequality into an equation: \(-x + y = 3\).
     - Find the intercepts:
        - When \(x = 0\), \(y = 3\) (point \((0,3)\)).
        - When \(y = 0\), \(x = -3\) (point \((-3,0)\)).
     - Draw the line through these points.
     - Shade the area above this line (since \(y\) is greater than or equal to the expression \(3 + x\)).
 
   - **Equation 3: \(x \geq 1\)**
     - This inequality represents a vertical line at \(x = 1\).
     - Draw the vertical line passing through \(x = 1\).
     - Shade the area to the right of this line (since \(x\) is greater than or equal to 1).

2. **Identify the Feasible Region**:
   - The feasible region is where all shaded areas intersect. To draw the polygon around
Transcribed Image Text:### Graphing Linear Inequalities: Feasible Region To understand how to graph the feasible region for a system of linear inequalities, we will analyze an example system and illustrate it on a Cartesian plane. Below is a system of inequalities and an empty graph where we can plot these inequalities to visualize the feasible region. #### System of Inequalities \[ \begin{cases} x + y \leq 8 \\ -x + y \geq 3 \\ x \geq 1 \end{cases} \] ### Steps for Graphing 1. **Graph each inequality separately**: - **Equation 1: \(x + y \leq 8\)** - Convert the inequality into an equation: \(x + y = 8\). - Find the intercepts: - When \(x = 0\), \(y = 8\) (point \((0,8)\)). - When \(y = 0\), \(x = 8\) (point \((8,0)\)). - Draw the line through these points. - Shade the area below this line (since \(y\) is less than or equal to the expression \(8 - x\)). - **Equation 2: \(-x + y \geq 3\)** - Convert the inequality into an equation: \(-x + y = 3\). - Find the intercepts: - When \(x = 0\), \(y = 3\) (point \((0,3)\)). - When \(y = 0\), \(x = -3\) (point \((-3,0)\)). - Draw the line through these points. - Shade the area above this line (since \(y\) is greater than or equal to the expression \(3 + x\)). - **Equation 3: \(x \geq 1\)** - This inequality represents a vertical line at \(x = 1\). - Draw the vertical line passing through \(x = 1\). - Shade the area to the right of this line (since \(x\) is greater than or equal to 1). 2. **Identify the Feasible Region**: - The feasible region is where all shaded areas intersect. To draw the polygon around
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