Given x + 5, x <-3 f(x) = {V9– x², 3 — х, -3 3 Find (a) lim f(x) (b) lim f(x) (c) lim f(x) (d) lim f (x) and lim f(x) X-3 X-3 X-4 x-5

Q: x3-3 3. Find lim f(x), . f(x) = %3D 3x3

A:

Q: 21 f(x)= 3x2 +4x +1 and g(x) = x2 -2x-3, then what is lim f(x) *→19(x)?

A:

Q: Find limx-&gt;∞,if for all x&gt;5

A: We apply limx-&gt;∞ on all sides.

Q: f(x + Ax) – f(x) Find lim Дх > 0 Ax f(x) 9x2 5x %3D teр 1 Find f(x + Ax) by substituting x + Ax in…

A:

Q: If 3x < f(x) < x³ + 2 for 0 < x < 2, find lim f(x). x-1

A:

Q: If f(x) = lim f(x) = X-4 -7 for x = 4, {2} 2x+7 for x #4 then

A:

Q: 5. Find lim f(x) f(x) 2 1 i -1 2 -2

A:

Q: If f(x) = |x-6| , then lim fx) – f(6) x - 6 f(x) – f(6) X - 6 lim X6*

A:

Q: ; Be h(x) = - 2x + 1, x + 3 calculate lim h(x) 7,x = 3 x-3

A:

Q: 3x2 (b) lim х30 х+1-ех

A:

Q: Stlon If f(x) = 6x³ 7x – 3, what is lim f(x)? – -

A:

Q: if f(2) = 4 f (2) = 1 Then Xf (2)-2г (x) lim x→2 X-2

A:

Q: f(x) If f(x) = 3x? + 4x +1 and g(x) = x² - 2x - 3, then what is lim *19(x)

A:

Q: 2r – 5x²/x Find lim x5/2 – 3x +1 — Зх + 1 X- 00

A:

Q: tan(14x) lim x→0 5x |

A:

Q: f(x) (28z +39)(2r 17)(5z 18)(7z 24) (24 7r)(5z 18)(28z +39)(39r 17) E) da como resultado:

A:

Q: If 2x – 2 < f(x) < x² – 2x + 2 for x 2 0, find lim f(x). X-2

A: The objective is to find the limit.

Q: If limx--3[x³ + f(x)] = -29, use the Rules of Limits to evaluate limx-3[36x2 + f(x)- 3x]. O a. 11 O…

A: The given limit limx→-3x3+fx=-29. We have to find the limit of limx→-336x-2+fx-3x.

Q: 1 c) lim x+0 \ex-1 X.

A: the given expression is: limx→01ex-1-1x…

Q: (-x² – 6x–10 xs-2 1. lim g(x), where g(x)={ x>-2

A:

Q: 2x + 12 4. Let f (x) = |X + 6| Determine (a) lim f (x) X→6+ (b) lim f (x) X→6- (c) limf(x) X→6

A:

Q: f(7+h) – f(7) lim h>0 h here f(x) = 7r +4. If the limit does not exist enter DNE.

A:

Q: x-2 22. Evaluate lim x+2 Vx2-4

A:

Q: S 3x + 2 x² + 3x – 1 I-2 |

A: Given that: f(x)=3x+2            x&lt;-2x2+3x-1   x≥-2

Q: If lim x-4 x-2 f(x)-5 - =1, find lim f(x) X-4

A:

Q: Evaluate lim f(x), f(x) = (3x² + 5x − 1, (7x² - 2x - 3, x ≤ 2 x > 2

A: Topic:-  limit and continuity

Q: if f(2) = 4 f(2) = 1 Then Xf(2)-2г (х). X- 2 lim x-2

A: