Given vectors A = 3ax + 4ay + az and B = 2ay – 5az, find the angle between A & B.

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Evaluate the following quantities and express your result in polar form. Show the step by step solution. Let 71 = 5+5i and Z2 = 6 + 3i, a. (Z1+Z2)Z1* b. (Z1+Z2)/Z2 c. (Z1- Z2)*

answer question  number 15 write the solution in a paper

Given two vectors R = 10 ax – 6ay + 5az and S = 0.1 ax + 0.2 ay + 0.3 az, calculate: a. Dot product of R and S b. Angle between R and S c. Cross product of the two vectors d. Unit vector from R to S

Solve for the complex variable v. Express the answer in rectangular form

We can use Eq. 1.7 to find A A = 7 and B = 4) and the angle Then we get: 26. Find the angle between A = -5i - 3j + 2k and B -2j - 2k. [Ser4 7-20] Eq. 1.7 allows us to find the cosine of the angle between two vectors as long as we know their magnitudes and their dot product. The magnitudes of the vectors A and B are: (−5)² + (−3)² + (2)² = 6.164 B = and their dot product is: A B = AB cos = (7)(4) cos 60° = 14 A = A² + A² + A² = = which then gives A · B = AxBx+ AyBy + A₂B₂ = (−5)(0) + (−3)(−2) + (2)(−2) = 2 1.2. WORKED EXAMPLES √B²+ B²+ B² = √(0)² + (−2)² + (−2)² = 2.828 B. We have the magnitudes of the two vectors (namely between the two is = 130° 70° = 60°. Then from Eq. 1.7, if o is the angle between A and B, we have 2 (6.164) (2.828) This gives us: coso = From which we get by: A.B AB = 27. Two vectors a and b have the components, in arbitrary units, ax = 3.2, ay = 1.6, b = 0.50, by = 4.5. (a) Find the angle between the directions of a and b. (b) Find the components of a vector c that…

Q. Two vectors are defined as A = a,+ 5 ay + 3a, and B = 3a,+2ay + a,. Which of the following vector is perpendicular to (A+ B) -4ax+4ay %3D 4ay+4az None of these axt az

V=x2y+y3+xz4 Find the gradient of the scalar?